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andreev551 [17]
3 years ago
5

Please Help Me!!!I will mark Brainliest!!!

Chemistry
1 answer:
il63 [147K]3 years ago
6 0

Answer:/

Explanation:

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Hexokinase iv has a km value that is substantially higher than the km for other hexokinases. what is the significance of this fa
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The Km is the MIchealis-Menten constant and this represents the affinity of the enzyme to its substrate. The higher the value for Km, the higher is the affinity of the enzyme to a substrate and the greater is the rate of reaction. Hexokinase IV has a higher Km than other hexokinases because it has a higher affinity to hexose substrates.
8 0
3 years ago
KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = \Delta T=T_f-T_i

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

Q = mc\Delta T

Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= \frac{10.1 g}{101 g/mol}=0.1 mol

KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)

The heat of solution =

\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol

So, the equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

4 0
4 years ago
Which statements are true of solutions?
Dimas [21]

Answer: they contain solutes and solvents, their particles must be evenly distributed, they may contain solid liquid and gas simultaneously, and they are homogeneous matter.

Explanation:

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3 years ago
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The following reaction shows sodium carbonate reacting with calcium hydroxide.
velikii [3]

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


5 0
3 years ago
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