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3 years ago

A fair die is thrown, What is the probability gained if you are told that 4 will

Engineering

1 answer:

Semmy [17]3 years ago

7 0

Answer:

1/6

Explanation:

A dice has 6 sides, the probability of 4 appearing is 1/6.

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Consider a C.T. system in s-plane below. Draw DF1 (Direct Form 1) realization. (by hand) Perform system realization using MATLAB

spin [16.1K]

Answer:

See the attached file for the answer.

Explanation:

See the attached file for the explanation

5 0

3 years ago

An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500

Assoli18 [71]

Answer: The exit temperature of the gas in deg C is $32^{o}C$ .

Explanation:

The given data is as follows.

$C_{p}$ = 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

$P_{1}$ = 100 kPa, $V_{1} = 15 m^{3}/s$

$T_{1} = 27^{o}C = (27 + 273) K = 300 K$

We know that for an ideal gas the mass flow rate will be calculated as follows.

$P_{1}V_{1} = mRT_{1}$

or, m = $\frac{P_{1}V_{1}}{RT_{1}}$

= $\frac{100 \times 15}{0.5 \times 300}$

= 10 kg/s

Now, according to the steady flow energy equation:

$mh_{1} + Q = mh_{2} + W$

$h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}$

$C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}$

$(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}$

$(T_{2} - T_{1})$ = 5 K

$T_{2}$ = 5 K + 300 K

$T_{2}$ = 305 K

= (305 K - 273 K)

= $32^{o}C$

Therefore, we can conclude that the exit temperature of the gas in deg C is $32^{o}C$ .

8 0

4 years ago

These are my dream cars there is more but it will only let me put 5

LekaFEV [45]

Answer:

niceeeeeeeeeeeeeeeeeee

4 0

3 years ago

A 25 kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water

defon

Answer: water at 18°C, w cw = 4.18 kJ/kg∙°C; at 27oC, Cfe = 0.554 kJ/kg∙°C. (Note that we could also have the following units for the heat capacities: kJ/kg∙K.) Assuming that the heat capacities are constant we have the following

The final temperature of the iron and the water will be the same: Tfe,2 = Tw,2 = T2. Substituting T2 for Tfe,2 and Tw,2, and solving for T2 gives the following result for the final temperature.

T2= ((Mw. Cw.T1w) + (Mfe.Cfe. T1fe))/((Mw.Cw) + (Mfe.Cfe))...equ 1

Where Me= mass of water= 100kg, Mfe =mass of iron = 25kg, T1fe = temp of iron before= 280°c,

Using substitution

T2= ((100*4.18*18) + (25*0.554*280))/ ((100*4.18) + (25*.554))

T2 = 26.4°c

So determine total entropy change

DStot = DSw + DSfe ...equat3

DStot = final entropy, DSw = entropy of water at T2, DSfe = final entropy of iron at T2 where,

DS = M.C. lin(T2/T1)...equ 5 temp is in Kelvin.

DSw = 100*4.18*lin(299.4/291) = 11.895

DSfe = 25*.554*lin(299.4/553) = -8.498.

Substituting answers into equa3

DStot = 11.895 - 8.498 = 3.397kj/kg*Kelvin

Explanation: the explanation is in the answers above..

3 0

3 years ago

technician a says that dynamic voltage is the voltage (usually of a battery) that exists without a load being applied. technicia

Artist 52 [7]

The battery electrolyte's specific gravity can be used to test the status of charge of a battery cell in the most precise and direct manner possible.

The state of charge increases with the specific gravity of the electrolyte. Voltage is the difference in electric potential between a battery's two terminals. The unit of measurement for voltage is called a volt (V), after the battery's creator, John Volta. An electronic tool called a state-of-charge battery tester is made to check the life and rechargability of an electric battery. A battery's current charging status and voltage output can be provided by a state-of-charge tester, which can also look for any defects that might impair the battery's overall performance.

Learn more about battery here-

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8 0

1 year ago