The speed of spaceship moving is 2.4 x 10^8 m/s
As from the given data, the clock in a spaceship is observed to run at a speed of 3/5 of a similar clock that rest on the earth is
T/T° = 3/5
The expression for the time dilation is given by
T = γT°
γ = T/T°
γ = 1/√1 - v^2/c^2 is time dilation
Substituting the values in the above equation as,
γ = T/T°
5/3 = 1/√1 - v^2/c^2
v^2/c^2 = 16/25
v = 0.8 c
v = 0.8 x 3 x 10^8 m/s
v = 2.4 x 10^8 m/s
Hence, speed of spaceship moving is 2.4 x 10^8 m/s
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Answer:
The bus
Explanation:
a = (v-u)/t
Where
a = acceleration
v = final velocity
u = initial velocity
t = time taken
For truck to get its acceleration,
a = (18-0)/5.5 = 3.27 ms⁻²
For bus to get its acceleration,
a = (24-0)/6 = 4 ms⁻²
As 4 > 3.27 bus has a greater acceleration.
This is simple question and easy to understand.
so first you use a formula to calculate frequency of the wave.
v _ stands for velocity a.k.a speed
f_ stands for frequency which you have to find.
(pronounced lemda)_ stands for wavelength.
Then you gonna place all your values according to you have in the formula as shown then solve for f.
Finally, you use the time formula
where
T_ is period a.k.a time which equal to the reciprocal of frequency or equal to 1/f.
Simply input your values according to the formula and you your answer as 0.5s