Answer:
Density of the liquid.
Explanation:
Density is the mass per unit volume of a substance.
At specific volume of each immiscible substance, the substance with lower relative molecular mass has the lower density and such floats.
Thus, the physical properties that determines the solvent layer that will be on top is DENSITY.
A hydrogen bomb is a nuclear bomb, like an atomic bomb, where the explosive energy comes from as nuclear reaction.
A hydrogen bomb is about fusion — fusing atomic nuclei together to combine into bigger ones.
A hydrogen bomb, or a thermonuclear bomb, contains a fission weapon within it but there is a two-stage reaction process.
The U.S. used two atomic bombs in World War II against Japan, Then, in 1952 and 1954
In particular, monitors will be looking for isotopes of a gas called xenon, which is typically present in H-bomb reactions.
Answer:
3.38 moles of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4CH2OH + 5O2 → 4CO2 + 6H2O
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.
Thus, 3.38 moles of O2 is required.
Let the total mass of compound is 100g
The mass of each element will be
Al = 22.10 g
P = 25.40 g
O = 52.50 g
In order to determine the molecular formula we will calculate the molar ratio of the given elements
Atomic weight of Al : 27 g/ mol
Atomic weight of P : 3 1g /mol
Atomic weight of O : 16 g /mol
Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819
Moles of P = mass / atomic mass = 25.40/ 31 = 0.819
Moles of O = mass / atomic mass = 52.50/ 16 = 3.28
Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present
moles of Al = 0.819 / 0.819 = 1
moles of P = 0.819 / 0.819 = 1
moles of O = 3.28 / 0.819 = 4
So the empirical formula will be : AlPO4
