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3 years ago

What is the definition of a molecule?

Chemistry

1 answer:

Doss [256]3 years ago

7 0

Answer:

A group of Adam's bonded together representing the smallest size find a mental unit of a chemical compound that can take part in a chemical reaction.

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The process of cellular respiration occurs in

EleoNora [17]

Answer: plants and animal cells

Explanation:

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2 years ago

5. Given the cell notation Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s), what is the half-reaction that occurs at the anode?

Nataly_w [17]

What is [H+] given that the measured cell potential is -0.464 V and the anode reduction ... What half-reaction occurs at the cathode during the electrolysis of molten ... PbO2(s) + 4H+(aq) + SO42-(aq) + 2e- → PbSO4(s) + 2H2O(l); E° = 1.69 V .... For the cell Cu(s)|Cu2+||Ag+|Ag(s), the standard cell potential is 0.46 V. A cell ... hopw this helps

3 0

3 years ago

Read 2 more answers

15.00 g of NH4HS(s) is introduced into a 500. mL flask at 25 °C, the flask is sealed, and the system is allowed to reach equilib

Ahat [919]

Answer:

0.328 atm

Explanation:

Kp is the equilibrium constant calculated based on the pressure, and it depends only on the gas substances. It will be the multiplication of partial pressures of the products raised to their coefficients divided by the multiplication of partial pressures of the reactants raised to their coefficients.

For the equation given, the stoichiometry is 1 mol of NH₃ for 1 mol of H₂S, so they will have the same partial pressure in equilibrium, let's call it p. So:

Kp = pxp

0.108 = p²

p = √0.108

p = 0.328 atm, which is the partial pressure of the ammonia.

3 0

3 years ago

In one experiment 7.62 g of Fe are allowed to react with 8.67 g of S

vichka [17]

calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess

moles = mass / molar mass

moles Fe = 7.62 g / 55.85 g/mol

= 0.1364 moles

1 mole Fe produces 1 mole FeS

Therefore 7.62 g Fe can form 0.1364 moles FeS

moles S = 8.67 g / 32.07 g/mol

= 0.2703 moles S

1 mole S can from 1 moles FeS

So 8.67 g S can produce 0.2703 moles FeS

The limiting reagent is the one that produces the least product. So Fe is limiting.

The maximum amount of FeS possible is from complete reaction of all the limiting reagent.

We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.

Convert to mass

hope this helps :)

4 0

3 years ago

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

5 0

3 years ago