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3 years ago

what is the end result of a chemical reaction(As it pertains to the properties of the substances made)

2 answers:

7 0

The end results of a chemical reaction are 1. a new substance is formed
2. a new color
3. bubbles/ air is produced
4.change in shape

Effectus [21]3 years ago

6 0

Answer:

Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products.

Explanation:

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Instantaneous speed is measured

torisob [31]

By using a tangent line.

I need a bit more info to be sure but that's not wrong.

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3 years ago

A baseball has a mass of 0. 45 kg and is thrown with a speed of 25 m/s. What is the momentum of the baseball? 0. 018 kg â€˘ mete

aleksandr82 [10.1K]

Answer:

11 Kg.m/s

Explanation:

P=mv

P=0.45*25

P=11.25 Kg.m/s

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2 years ago

Define, identify, and differentiate different forms of energy

slava [35]

the difference is that a source is where u get it from and a form is the type of energy. the difference is that a source is where u get it from and a form is the type of energy.

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4 years ago

15 points and will mark as a brainlest PLEASE

vekshin1

It is E pls mark me braliest

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3 years ago

Read 2 more answers

Tarzan (mT=85.0 kg) is perched on a cliff 16.0 m above Jane. Jane is in the foreground is looking forwards. In the background, T

poizon [28]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Part A

The velocity of Tarzan is $v_T = 17.7 \ m/s$

Part B

The percentage loss of kinetic energy is %-loss $= 61.4$ %

Part C

The speed would be exactly the same

Explanation:

From the question we are told that

The mass of Tarzan is $m = 85.5 \ kg$

The height of the cliff is $h = 16.0 \ m$

From the law of conservation of energy

$PE = KE$

Where PE is the potential energy of Tarzan at the top of the cliff which is mathematically represented as

$PE = mgh$

KE is the kinetic energy of Tarzan as he swings toward jane and is mathematically represented as

$KE = \frac{1}{2} mv^2_T$

$mgh = \frac{1}{2}m v_T^2$

=> $gh = \frac{1}{2} v_T^2$

Substituting values

$9.8 * 16 = \frac{1}{2} v_T^2$

=> $v_T = \sqrt{\frac{9.8 * 16}{0.5} }$

$v_T = 17.7 \ m/s$

From the question we are told that the actual velocity of Tarzan is

$v = 11 m/s$

The kinetic energy at the the velocity is mathematically represented as

$KE_A = \frac{1}{2} m v^2$

Substituting values

$KE_A = \frac{1}{2} (85) * 11^2$

$KE_A = 5142.5 J$

The kinetic energy at $v_T$ is

$KE = \frac{1}{2} * 85 * 17.7^2$

=> $KE = 13314.83\ J$

Now the percentage loss of kinetic energy is mathematically evaluated as

%-loss $= \frac{KE - KE_A}{KE} * 100$

substituting values

%-loss $= \frac{13314.83 - 5142.5}{13314.83} * 100$

%-loss $= 61.4$ %

The mass of Tarzan does not affect the speed because looking at this equation

$gh = \frac{1}{2} v_T^2$

We see that the velocity of Tarzan is not dependent on the mass of Tarzan

4 0

3 years ago