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MrRissso [65]
3 years ago
8

What does a pH of 7 say about a solution?

Chemistry
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

B

Explanation:

it shows that the solution is neutral.

I hope this helps

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what is the greatest amount of bread rolls that can be made with 6 cups of flour And 3 cups of water? If this were a chemical re
forsale [732]

Answer:

if you tell me how much is needed and how much you have then i can answer it, but there is not enough information provided to answer to that question.

Explanation:

7 0
2 years ago
Whoever answers correctly I’ll give you a Brainly
Andre45 [30]

Answer:

answer is B

Explanation:

3 0
2 years ago
Read 2 more answers
A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol
Marat540 [252]

Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

                               1 gallon = 3.78541 L

                               4. 50 gallon = 3.785 L x 4.50

So,                        

initial volume V1 =  17.03 L

final Volume V2 = ?

initial Temperature T1  = 80° F

convert Temperature to Kelvin

                              T1 = ( 80° F -32) / 1.8 +273

                               T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

                                  T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

                      V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

                      V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

V2 =  17.03 L x 373 K / 299.7 K

V2 =  21. 19 L

So the final volume of Methane gas = 21.19 L

Or for Volume in gallons

1 L = 0.26

21.19 x 0.264 = 5.6 gallons

7 0
3 years ago
Write the molecular formula of ferric oxide and calcium hydroxide by criss-cross method ​
irina [24]
<h3>Ferric Oxide:-</h3>

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Fe}\put(0,0){\bf -3}\put(4,3){\sf O}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}

\\ \sf\longmapsto Fe_2O_3

<h3><u>C</u><u>a</u><u>l</u><u>c</u><u>i</u><u>u</u><u>m</u><u> </u><u>H</u><u>y</u><u>d</u><u>r</u><u>o</u><u>x</u><u>i</u><u>d</u><u>e</u><u>:</u><u>-</u></h3>

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Ca}\put(0,0){\bf 2}\put(4,3){\sf OH}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}

\\ \sf\longmapsto Ca(OH)_2

4 0
3 years ago
The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
3 years ago
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