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Tatiana [17]
3 years ago
7

Silver is the metal with the highest conductivity, followed by copper, gold and aluminium. Why do you think copper and aluminium

are used for electrical wire and cable rather than silver and gold?
Chemistry
1 answer:
Olegator [25]3 years ago
3 0

Explanation:

Copper and aluminum are used for electric wires and cables because they are readily available and cheaper to produce.

The abundance of copper and aluminum is higher compared to silver and gold.

This makes the metals easier to mine than silver and gold. It would be impossible to use the scare amount of gold and silver to make electric wires and cables.

This use cannot be sustained.

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Nikitich [7]
Check the attached file for the answer.

5 0
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How did the atmosphere get its oxygen
riadik2000 [5.3K]
Because super tiny organisms called cyanobactierea (alge) they conducted photosynthesis and they us sunshine water and Carbon D to make Oxygen
7 0
4 years ago
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What volume in mt, of 0.5a M1HCI solution is needed to neutralize 77 ml of 1.54 M NaOH solution?
Rainbow [258]

Answer:

237.2 mL.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HCl = (XMV) NaOH.</em>

<em></em>

For HCl; X = 1, M = 0.5 M, V = ??? mL.

For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.

<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>

8 0
3 years ago
When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C
natka813 [3]

Answer:

\Delta_{r}U of the reaction is -6313 kJ/mol

\Delta_{r}H of the reaction is -6312 kJ/mol

Explanation:

Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C

q_{cal}= C \times \Delta T

=5.861 \times 3.596 = 21.076\,kJ

q_{rxn}= -q_{cal}= -21.076\,kJ

\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol

Therefore, \Delta_{r}U of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter  is as follows.

C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)

Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5

\Delta_{r}H=\Delta E+ \Delta n. RT

=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol

Therefore, \Delta_{r}H of the reaction is -6312 kJ/mol.

3 0
3 years ago
Calculate the density of a material that has a mass of 56.6 g and a volume of 17.2 cm
Cerrena [4.2K]

Answer:

d = 3.29 g/cm³

Explanation:

Given data:

Density of material = ?

Mass of material = 56.6 g

Volume of material = 17.2 cm³

Solution:

Formula;

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 56.6 g/ 17.2 cm³

d = 3.29 g/cm³

4 0
3 years ago
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