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Flauer [41]
3 years ago
13

Use the image to answer the question. Which process enables the boy to see over the wall?

Chemistry
1 answer:
professor190 [17]3 years ago
5 0

Answer:

refraction

reflection

by

reflecting

over

the

mirror

Explanation:

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!!PLEASE ANSWER!! 24 PTS!!
Thepotemich [5.8K]

1.magnesium

2.magnesium

6 0
3 years ago
Mass is 5 grams and the volume is 4.5 grams what is the density
STatiana [176]
Density = Mass/Volume

d= 5 / 4.5
8 0
3 years ago
A/1 * B/C = D
grigory [225]

Answer : 4.8 florins can you exchange for your 4 guilders.

Solution : Given,

The current exchange rate for every 2.4 florins is 2.0 guilders

As per question,

The exchange rate is 2.0 guilders for every 2.4 florins

The exchange rate is 1 guilders for every \frac{2.4}{2.0} florins

The exchange rate is 4 guilders for every \frac{2.4}{2.0}\times 4=4.8 florins

Therefore, the 4.8 florins can you exchange for your 4 guilders.


3 0
3 years ago
When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.
Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

\Delta T=32.3-25.0\ ^0C=7.3\ ^0C

So,  

\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J

Also, 1 J = 0.001 kJ

So,  

\Delta H=0.03189\ kJ

Also, Molar mass of CaO = 56.0774 g/mol

Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol

Thus, Enthalpy change in kJ/mol is:-

\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol

8 0
3 years ago
Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 x 10-8.
Misha Larkins [42]
Use the ICE table approach as solution:

           PbSO₄   --> Pb²⁺ + SO₄²⁻
I             -                 0          0
C           -                +s         +s
E           -                  s          s

Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = <em>1.35×10⁻⁴ M</em>
5 0
3 years ago
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