Answer:
For electric field inside cylinder, check image 02 attached
For electric field outside cylinder, check image 03 attached
Explanation:
Let's consider the polarized cylinder as superposition of two cylinders with opposite,equal, uniform charge densities in a way shown in the figure in the "image 01"d attached ;
In general, if we have an object with polarization (P¬) , then we have to take two objects with similar shape to the system, with opposite, equal, and uniform charge densities and then we super-impose these two objects in such a way that the total dipole moment of this superimposed system is equal to the total dipole moment of original system.
Now, we can take the super- imposed system as equivalent to the original system for calculating electric field and potential.
Therefore,
For the electric field inside the cylinder, check the solution in "image 02" i attached
For the electric field outside the cylinder, check, "image 03" i attached.
d. lower frequencies and low energy.
Explanation:
Microwaves and infrared waves are lower frequencies and lower energy waves.
They are both non-ionizing radiation.
- Microwaves and infrared waves are both electromagnetic waves.
- They do not require a material medium to be propagated in nature.
- They have little energy because the have very low frequency.
- They also have very long wavelengths.
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Electromagnetic radiation brainly.com/question/7590814
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Answer:
600 KPa.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 0.075 m³
Final volume (V2) = 0.45 m³
Final pressure (P2) = 100 KPa
Initial pressure (P1) =?
Temperature = constant
The initial pressure can be obtained by using the Boyle's law equation as shown below:
P1V1 = P2V2
P1 × 0.075 = 100 × 0.45
P1 × 0.075 = 45
Divide both side by 0.075
P1 = 45 / 0.075
P1 = 600 KPa.
Thus, the initial pressure in the balloon is 600 KPa.
Answer:
Explanation:
an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Answer:
14J
20000J
200J
Explanation:
formula :W=FS
W:work done
F:force (N)
S:displacement moved in direction of force (m)
1) 20N×0.7m
=14J
2) 400N×50m
= 20000J
3) 10N×20m
=200J