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daser333 [38]
3 years ago
12

The following reaction is performed at STP. If 0.64 liters of NH3 is produced, how many liters of nitrogen gas should go into th

e reaction?
N2 + 3H2 --> 2NH3


0.65 liters N2


0.32 liters N2


1.28 liters N2


2.74 liters N2
Chemistry
1 answer:
frozen [14]3 years ago
6 0

Answer:

0.65

Explanation:

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Can someone explain the steps for balancing chemical equations in depth?
m_a_m_a [10]

Answer:

Steps explained below

Explanation:

To explain balancing of chemical equations, I will make use of an example equation where Hydrogen and oxygen react to form water.

H2 + O2 = H2O

Now, the equation I've listed above is an unbalanced chemical equation. It can be balanced by the following steps;

Step 1: Identify the elements on both the left Hand side and the right hand side.

In this case;

on the left hand side, we have H and O.

On the right hand side, we have H and I also.

Step 2: Identify the number of atoms of each element on both the left and right hand sides.

On the left, H has 2 atoms and O has 2 atoms.

On the right, H has 2 atoms and O has 1 atom.

Step 3: For the equation to be balanced, the number of atoms of each element on the right and left hand side must be the same.

Thus,

O on the left hand side has 2 atoms but on the right hand side it has 1 atom. Thus, we will multiply O on the right by 2 to balance what we have on the left.

So, we now have;

H2 + O2 = 2H2O

Step 4: Check equation: We now have;

H2 + O2 = 2H2O

Our left hand side remains 2 atoms of H and 2 atoms of O. But on the right, we now have;

2 atoms O and 4 atoms of H.

Which means atoms of H is not balanced with the left side.

Step 5: rebalance equation: To rebalance, we multiply H on the left by 2 to give us 2 × 2 = 4 atoms.

Thus, we now have;

2H2 + O2 = 2H2O

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On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of
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Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

C\propto P

C=K_H\times P

K_H is Henry's constant.

or,

\frac{C_1}{C_2}=\frac{P_1}{P_2}

where,

C_1 = initial concentration of gas = 5.3\times 10^{-4}M

C_2 = final concentration of gas = 2.0\times 10^{-3}M

P_1 = initial partial pressure of gas = 0.78 atm

P_2 = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

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What will be the pH of a buffer solution containing an acid of pKa7.5, with an acid concentration exactly one fourth of that of
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Answer:

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Explanation:

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