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exis [7]
4 years ago
15

The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2,716.5 feet) and has more than 160 stories.

A tourist is obviously using the elevator to reach their hotel room and after a long ride finally arrives at the correct floor where the tourist has − 187000 J of potential energy. If the 184 lb tourist has zero potential energy at the top of the building, what is the height h of the hotel room above the ground? The acceleration due to gravity is 9.81 m/s2.
Physics
1 answer:
Elena L [17]4 years ago
4 0

Answer:

 h = 599.5 m

Explanation:

Given,

height of structure = 828 m

weight of the tourist = 184 lb

                                 = 184 x 0.45359 = 83.43 Kg

Potential energy = 187000 J

PE = m gd

d = \frac{PE}{mg}

d = \frac{187000}{83.43\times 9.81}

h = 228.5 m

Height of the room above the ground.

 h = 828 - 228.5

 h = 599.5 m

Height of the floor above ground is equal to 599.5 m.

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To solve this problem we will apply the concepts related to potential gravitational energy. This is defined as the product between mass, acceleration and change in height and can be expressed as,

\Delta PE = mg \Delta h

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Complete Question

Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperature of 2.81 K. Remember that Stefan's Law gives the Power (Watts) and Intensity is Power per unit Area (W/m2).

Answer:

The intensity is I  = 3.535 *10^{-6} \  W/m^2

Explanation:

From the question we are told that

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Where  \sigma is the Stefan Boltzmann constant with value  \sigma  =  5.67*10^{-8} m^2 \cdot kg \cdot s^{-2} K^{-1}

  Now the intensity of the cosmic background radiation emitted according to the unit from the question is mathematically evaluated as

        I  =  \frac{P}{A}

=>      I  =  \frac{\sigma *  A  * T^4}{A}

=>      I  =  \sigma  *  T^4

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