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saul85 [17]
3 years ago
14

Why are earths rocks generally younger than earth itself.

Physics
2 answers:
serious [3.7K]3 years ago
5 0

Answer:

The lack of impact craters and the age of most rocks on Earth in comparison to other bodies in the solar system can be attributed to processes such as volcanism, plate tectonics, and erosion that have reshaped Earth's surface, and this is why most of Earth's rocks are much younger than the Earth itself.

iren2701 [21]3 years ago
3 0

Answer:

The reason why the rocks are more younger than Eart itself is because they come from processes like plate tectonics, volcanoes, and erosions that made up Earth's surface.

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Why transparent object don't form a shadow​
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Explanation:

Transparent objects do not form shadows. The light passes completely from the transparent objects thus these objects will not form shadow. ... In such objects, the light gets refracted thus, such objects forms shadow. The refraction is also the reason why we can see such objects.

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3 years ago
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The density of water is 1.00 g/cm3. What is its density in kg/m3?
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1 g = 1 ÷ 1000 kg
= 0.001 kg

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3 years ago
What statement is true about earth tectonic plates
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<span>
Paleomagnetism, magnetic field placement in the layers of the rock are present.</span>
3 0
4 years ago
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A bungee jumper launches herself off a bridge, how would you describe her motion?
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3 years ago
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On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m
Nastasia [14]

Answer:

F = 1.489*10^{-7}  N

Explanation: Weight of space probes on earth is given by:W= m*g

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 \frac{m}{s^{2} })

Therefore,

m_{1} = \frac{14500}{9.81}

m_{1} = 1478.08  kg

Similarly,

m_{2} = \frac{4800}{9.81}

m_{2} = 489.29  kg

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

F =  \frac{Gm_{1} m_{2}}{R^{2} }

G= gravitational constant (6.67 * 10^{-11} m^{3} kg^{-1} s^{-2})

m_{1} , m_{2}= masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

F = 1.489*10^{-7}  N

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

7 0
4 years ago
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