Answer:
A) A warm wire
Explanation:
A warm wire has the most resistance. Heating the metal wire causes atoms to vibrate more, which in turn makes it more difficult for the electrons to flow, increasing resistance. Heating the wire increases resistivity.
Answer:
The work done on the system can be accounted for by;
Both and
Explanation:
The speed of the crate = Constant
Therefore, the acceleration of the crate = 0 m/s²
The net force applied to the crate, = 0
Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate
However, we have;
The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate
The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system
The weight of the crate × The height the crate is raised = Gravitational Potential Energy =
The heat generated as internal energy to the system =
Therefore;
The work done on the system = + .
The metals are the elements that more easily can lose electrons to fill their outermost shell. And among the metals the alkalyne are most likely than alkalyne earth and these are most likely than other metals.
As less electrons the metal has in its outermost shell the more likely it will lose an electron fo fill its outermost shell.
So, Li, Na, K, Rb, Cs, and Fr have one electron in their outermost shell, so they are more likely to lose an electron to fill their outermost shell than Be, Mg, Ca, Sr, Ba, Ram which have two electrons in their outermost shell.
Using the same reasoning, Be, Mg, Ca, Sr, Ba, Ra are more likely to lose an electron to fill its outermost shell than Al, Ga, In, Tl.
Al, Ga, In, Tl are more likely to lose an electron than Si, Ge, Sn, Pb.
Si, Ge, Sn, Pb are more likely to lose an electron than O, S, Se, Te, Po
O, S, Se, Te, Po are more likely to lose an electron than F, Cl, Br, I, At
F, Cl, Br, I, At (halogens) and He, Ne, Ar, Kr, Xe, Rn (noble gases) will not likely lose electrons.