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2 years ago

Find the vector v with the given magnitude and the same direction as u. Magnitude ||v|| = 10 Direction u = ⟨-3. 4⟩.

Physics

1 answer:

Alisiya [41]2 years ago

4 0

Answer:

(-6,8)

Explanation:

Since v has direction as u, it must be a multiple n of u.

$\sqrt{(-3n)^+(4n)^2}=10\\9n^2+16N^2 =100\\n^2=4\\n=2$

therefore v = (3×2, 4×2) = (-6,8)

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masya89 [10]

Answer:

Explanation:

Given

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3 years ago

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3 years ago

A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the

jasenka [17]

Answer:

1.8 cm

Explanation:

$m$ = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

$q$ = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

$\Delta V$ =Potential difference through which the ion is accelerated = 215 V

$v$ = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

$(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}$

$r$ = Radius of the path followed by ion

$B$ = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

$qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm$