Answer
given,
Weight of the child = 110 N
length of the swing,L = 2 m
now, calculating the potential energy when the string is horizontal
Potential energy = m g h
now, h = L (1 - cos θ) where θ is the angle made by the string with the vertical.
PE = m g L (1 - cos θ)
when rope is horizontal θ = 90°
PE = 110 x 2 (1 - cos 90°)
PE = 220 J
now, calculating potential energy when string made 25° with horizontal
PE = m g L (1 - cos θ)
when rope is horizontal θ = 25°
PE = 110 x 2 (1 - cos 25°)
PE = 20.61 J
Answer:
50m/s, 187.5m
Explanation:
Consider unit analysis:
m/s² = m/(s×s)
This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.
Velocity is being increased per second, and this is called acceleration:
a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1
From the question, we have the variables:
a = 5m/s²
(delta)v = v2 - 25m/s
(delta)t = 5s (initial time is 0)
a = v/t
(5m/s^2)=v/5s
25m/s = v2 - 25m/s
50m/s = v2
The final velocity of the vehicle is 50m/s.
A formula exists to find displacement with regards to acceleration:
d=v(initial) × t +1/2 × a × t²
d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²
d=125m+1/2×125m
d=125m+62.5m
d=187.5m
The distance travelled by the vehicle is 192.5m.
<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>
Answer:
y = 1.75 cm
Explanation:
In the double-slit experiment the equation for destructive interference is
d sin tea = (m + ½)
λ
let's use trigonometry to find the angle
tan θ = y / L
as all the experiment does not occur at small angles
tan θ = sin θ / cos θ = sin θ = y / L
we substitute
y = (m + 1/2 ) λ L / d
we calculate
y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³
y = 1.75 10⁻² m
y = 1.75 cm
The answer will be B) Meter
Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)
=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)
=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
