All categories

2 years ago

HELP!!

Mathematics

2 answers:

lbvjy [14]2 years ago

8 0

Answer: Only Ingrid

Step-by-step explanation:

mina [271]2 years ago

4 0

Answer:

only ingrid

Step-by-step explanation:

You might be interested in

Graph the inverse circular function by hand, given f(x) = 3sin(2x) ;-pi/4 ≤ ≤pi/4

nasty-shy [4]

Part a)

a) The given function is

$f(x) = 3 \sin(2x)$

We let

$y = 3 \sin(2x)$

Interchange x and y.

$x= 3 \sin(2y)$

Solve for y;

$\frac{x}{3} = \sin(2y)$

$y = \frac{1}{2} { \sin}^{ - 1}( \frac{x}{3} )$

${f}^{ - 1}(x) = \frac{1}{2} { \sin}^{ - 1}( \frac{x}{3} )$

Part b) The range of f(x) refers to y-values for which f(x) exists.

The range of f(x) is

$- 3 \leqslant y \leqslant 3$

This is because the function is within y=-3 and y=3.

c) The range of

${f}^{ - 1} (x)$

$- \frac{ \pi}{4} \leqslant y \leqslant \frac{\pi}{4}$

The domain is -3≤x≤3

This is because the domain and range of a function and its inverse swaps.

Part d) The graph is shown in the attachment.

3 0

3 years ago

If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage

victus00 [196]

Answer:

The voltage is 10 + 2j volts.

Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

$V = R*i$

The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

Both the current and the resistance have complex parts. We have to know that:

$j^{2} = -1$

We have that:

$R = 3 - 2j, i = 2 + 2j$

Then

$V = R*i$

$V = (3 - 2j)*(2 + 2j)$

$V = 6 + 6j - 4j - 4j^{2}$

$V = 6 + 2j - 4(-1)$

$V = 10 + 2j$

The voltage is 10 + 2j volts.

4 0

3 years ago

Which of the following is an example of a proper fraction? A.7/6 B.3/4 C.4/4 D.4/3

statuscvo [17]

Answer: B

Step-by-step explanation:

A proper fraction is when a fraction has the numeration less than the denominator

3 0

3 years ago

A spinner is labeled 1 to 10. What is the probability of the spinner landing on a prime number after one spin?

BlackZzzverrR [31]

Answer:

40%

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Question (in need of help)

mr Goodwill [35]

<h3>Required Answer:-</h3>

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

${p}^{2} + {b}^{2} = {h}^{2}$

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

${9}^{2} + {11}^{2} = {h}^{2}$

Then,

$h = \sqrt{ {9}^{2} + {11}^{2} }$

$h = 14.12(approx.)$

<h3>Hence:-</h3>

The x of the right angled ∆ = 14.12

6 0

2 years ago

Read 2 more answers