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ANTONII [103]
3 years ago
5

HELP!!

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0

Answer: Only Ingrid

Step-by-step explanation:

mina [271]3 years ago
4 0

Answer:

only ingrid

Step-by-step explanation:

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Show me how to get this answer show your work
Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

MKL=2(15)+10 = 40\\ LKJ=3*15-5=40

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0
3 years ago
Read 2 more answers
How long would it take the two trains to meet?
tiny-mole [99]

Answer: 2.5 hours.

Step-by-step explanation:

7 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
How would you solve cos(5x)=sin(10x) ?
Tomtit [17]
We will use double angle identities:
cos (5x ) = sin (10x )   
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
5 x = π/2 +kπ,  k∈Z                        sin (5 x) = 1/2
x1 = π/10 + kπ/5                           5 x = π/6+2kπ    , k∈ Z
                                                       5 x = 5π/6 +2kπ , k∈ Z
                                                       x 2 = π/30 +2kπ/5
                                                       x 3 = π/9  + 2kπ/5
4 0
3 years ago
What do I do in an algebraic equation when x and y are connected (xy)?
tia_tia [17]

Answer: Distributive property

Step-by-step explanation: I do believe in questions like this you would distribute from the perenthisis (right?)

7 0
3 years ago
Read 2 more answers
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