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Alexxandr [17]
3 years ago
6

What will result from the Alpha decay of (17 8)O?

Chemistry
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

alpha decay, because alpha particles have two protons and two neutrons.  If the isotope has an atomic number two less than the original, it lost two protons, the same amount as in an alpha particle.

Explanation:

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The 5 branches are organic, inorganic, biochemistry, analytical, and physical. There are different branches because they each apply to different parts of chemistry. For example organic chemistry is the study of carbon compounds and inorganic chemistry is the study of non carbon compounds. You can't just have one type of chemistry because these are very different.
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How do chemical characteristics of rocks effect water
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<h2><u>Hope this helps→←</u></h2>
7 0
2 years ago
A solution of H2SO4(aq) with a molal concentration of 5.74 m has a density of 1.238 g/mL. What is the molar concentration of thi
Vika [28.1K]

<span>Molarity is expressed as the number of moles of solute per volume of the solution while molality is expressed as the number of moles solute per mass of solution. We calculate as follows:</span>

5.74 mol / kg (1.238 kg/L) = 7.10612 mol / L or 7.11 M

6 0
3 years ago
Part B When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8 g of carbon were burned in the pres
aksik [14]

<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carbon = 22.8 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol

The chemical equation for the reaction of carbon and oxygen gas follows:

C+O_2\rightarrow CO_2

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = \frac{1}{1}\times 1.9=1.9moles of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.9 moles

Putting values in equation 1, we get:

1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g

Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams

6 0
3 years ago
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