2 years ago

What will result from the Alpha decay of (17 8)O?

Chemistry

1 answer:

Nookie1986 [14]2 years ago

3 0

Answer:

alpha decay, because alpha particles have two protons and two neutrons. If the isotope has an atomic number two less than the original, it lost two protons, the same amount as in an alpha particle.

Explanation:

You might be interested in

Consider two solutions made using water as the solvent: 1.0 m CaCl2 and 3.0 m sucrose. Describe how the osmotic pressures of the

mash [69]

Osmotic pressure is calculated by the product of the concentration in molarity, the temperature, the vant Hoff factor (3 for CaCl2 and 1 for sucrose) and R, universal gas constant. At the same temperature, the osmotic pressures of both solutions are equal.

π = CRTi
For CaCl2,
π = (1)RT(3) = 3RT

For sucrose,
π = (3)RT(1) = 3RT

7 0

2 years ago

Read 2 more answers

What 2 ways that humans have contributed to desertifaction

sdas [7]

Deforestation and inappropriate agriculture otherwise known as over farming are factors of and causes of desertification.

8 0

2 years ago

The chemical formula for beryllium oxide is BeO.A chemist determined by measurements that 0.045 moles of beryllium participated

blondinia [14]

Answer: 0.405g

Explanation:

Molar Mass of Be = 9g/mol

Number of mole of Be = 0.045mol

Mass conc. Of Be = 0.045 x 9 = 0.405g

8 0

3 years ago

PLEASE HELP WITH CHEMISTRY !! BRAINLIEST AND 10 POINTS !!

NeTakaya

Answer:

c is your answer there u go

Explanation:

7 0

2 years ago

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

8 0

2 years ago