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Mnenie [13.5K]
3 years ago
14

What is intensity?

Physics
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer:

D

Explanation:

None of the above because the intensity is amount of a property, force, brightness, and magnetic field.

makkiz [27]3 years ago
3 0

<u><em>Answer:</em></u>

<em>D. None of the above</em>

<u><em>Explanation:</em></u>

<em>D. None of the above, because the quality or condition of being intense. great energy, strength, concentration, vehemence, etc., as of activity, thought, or feeling: He went at the job with great intensity. a high or extreme degree, as of cold or heat. the degree or extent to which something is intense.</em>

<em />

<em />

<u><em><>Hope this helps! : ) </em></u>

<u><em /></u>

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What evidence supported the Oscillating Big Bang?
stira [4]
<h2>Answer with Explanation </h2>

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This portrayal would just mean a certain something every one of the laws of material science will be tossed out of the window. This is naturally unsuitable to physicists. To exacerbate the situation, a few cosmologists even trust that the Universe will, in the end, achieve the greatest purpose of development and that once this occurs, it will at that point crumple into itself.

This will basically prompt indistinguishable conditions from when we extrapolate back to the snapshot of the Big Bang. To cure this difficulty, a few researchers are suggesting that maybe the Universe won't achieve the purpose of peculiarity all things considered.

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4 years ago
Why do people have symptoms in their bodys
weeeeeb [17]

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5 0
3 years ago
Read 2 more answers
Semi-trailer trucks have an odometer on one hub of a trailer wheel. The hub is weighted so that it does not rotate, but it conta
shtirl [24]

Answer:

1020 km

Explanation:

A complete rotation of the wheel equals a distance of 1 circumference.

The circumference is

C = \pi d

where <em>d</em> is the diameter of the wheel.

300,000 rotations = 300000\pi d = 300000\times\pi\times1.08\text{ m} = 1017876.0\ldots\text{ m}

In kilometers, this is = 1017876/1000 km = 1020 km

6 0
3 years ago
A hayride wagon is going down a spooky country road at 15 m/s when a Scarecrow appears in the roadway. The man at the wheel of t
nexus9112 [7]

Answer:

d = 68.18 m

Explanation:

Given that,

Initial velocity, u = 15 m/s

Finally it comes to stop, v = 0

Acceleration, a = -1.65 m/s²

Time, t = 2.5 s

We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(15)^2}{2\times -1.65}\\\\d=68.18\ m

So, the hayride will cover a distance of 68.18 m.

6 0
4 years ago
At an altitude of 5000 m the rocket's acceleration has increased to 6.9 m/s2 . What mass of fuel has it burned?
sergey [27]

1) Initial upward acceleration: 6.0 m/s^2

2) Mass of burned fuel: 0.10\cdot 10^4 kg

Explanation:

1)

There are two forces acting on the rocket at the beginning:

- The force of gravity, of magnitude F_g = mg, in the downward direction, where

m=1.9\cdot 10^4 kg is the rocket's mass

g=9.8 m/s^2 is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

T=3.0\cdot 10^5 N

According to Newton's second law of motion, the net force on the rocket must be equal to the product between its mass and its acceleration, so we can write:

T-mg=ma (1)

where a is the acceleration of the rocket.

Solving for a, we find the initial acceleration:

a=\frac{T-mg}{m}=\frac{3.0\cdot 10^5-(1.9\cdot 10^4)(9.8)}{1.9\cdot 10^4}=6.0 m/s^2

2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

a'=6.9 m/s^2

The reason for this increase is that the mass of the rocket has decreased, because the rocket has burned some fuel.

We can therefore rewrite eq.(1) as

T-m'g=m'a'

where

m' is the new mass of the rocket

Re-arranging the equation and solving for m', we find

m'=\frac{T}{g+a}=\frac{3.0\cdot 10^5}{9.8+6.9}=1.8\cdot 10^4 kg

And since the initial mass of the rocket was

m=1.9 \cdot 10^4 kg

This means that the mass of fuel burned is

\Delta m = m-m'=1.9\cdot 10^4 - 1.80\cdot 10^4 = 0.10\cdot 10^4 kg

3 0
3 years ago
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