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jok3333 [9.3K]
2 years ago
11

Element X forms an oxide with chemical formula X20. Experimental tests show that X20 contains 25.8 % oxygen, and x contains 74.2

% by mass.
(b) Use this information to identify element X.
Chemistry
1 answer:
lawyer [7]2 years ago
6 0
Hdhdhdh hdhdhdh hdhdhdh
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Which metal ion was green when placed in the fire?
Debora [2.8K]

Answer:

Barium Ba2+

Explanation:

Potassium lilac

Calcium orange red

Copeer blue green

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2 years ago
How many moles of copper are in 1.51 x 1024 Cu atoms?
kkurt [141]
<h3>Answer:</h3>

2.51 mol Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.51 × 10²⁴ atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})
  2. Multiply/Divide:                  \displaystyle 2.50747 \ mol \ Cu

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.50747 mol Cu ≈ 2.51 mol Cu

8 0
2 years ago
How many Joules must be removed to condense 150.0g of steam at 100.0 degrees Celsius to water at 100.0 degrees celcius
Elina [12.6K]

Answer:

339kJ

Explanation:

Given parameters:

Mass of steam  = 150g  = 0.15kg

Initial temperature of steam  = 100°C

Final temperature of water  = 100°C  

Unknown:

Quantity of heat that must be removed to condense the steam = ?

Solution:

The heat involved here is a latent heat because there is no change temperature. The process is just a phase change.

  H  = mL

m is the mass

L is the latent heat of vaporization  = 2,260 kJ/kg

Insert the parameters and solve;

 H = 0.15kg x 2,260 kJ/kg

 H  = 339kJ

7 0
3 years ago
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