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The wavelength of the interfering waves is 3.14 m.
<h3>Calculation:</h3>
The general equation of a standing wave is given by:
y = 2A sin (kx) cos (ωt) ......(1)
The given equation represents the standing wave produced by the interference of two harmonic waves:
y = 3 sin (2x) cos 5t .......(2)
Comparing equations (1) and (2):
k = 2
We know that,
k = 2π/λ
λ = 2π/k
λ = 2 (3.14)/ 2
λ = 3.14 m
Therefore, the wavelength of the interfering waves is 3.14 m.
I understand the question you are looking for is this:
Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t where x is in m and t is in s. What is the wavelength of the interfering waves?
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Answer:
Therefore, the car will cover a distance of 200 meters after 10 seconds.
<h2>
Please mark me as brainliest</h2>
Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is
.
Because the surface is flat, the radius of curvature is infinity .
The incident index is
and the transmitted index is
.
The single interface equation is 
Substituting the quantities given in the problem,

The image distance is then 
Therefore, the coin falls
in front of the target
Answer:
B.6.86 m
Explanation:
Given that
Compression in spring ,x= 9 cm
Spring constant ,K= 830 N/m
Mass of the rocket ,m= 50 g = 0.05 kg ( 1 kg = 1000 g)
Now by applying energy conservation


Now by putting the values ( we are taking g= 9.81 m/s²)

h= 6.853 m
Therefore the answer is B.
B.6.86 m