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Savatey [412]
3 years ago
5

A recently depolarized area of a cell membrane cannot generate an action potential because of the

Chemistry
2 answers:
Ann [662]3 years ago
8 0
It can not generate an action potential because of the absolute refractory period.
marysya [2.9K]3 years ago
4 0
The refractory period makes the cell rest. In this period, the cell becomes able to depolarize again by collecting ions.
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The picture above represents which of the following?
PSYCHO15rus [73]
This is a plant cell because there are chloroplasts in this diagram which are present in plant cells
6 0
3 years ago
When the pH decreases from 6 to 3, the hydrogen ion, H+, increases by what?
Irina-Kira [14]

pH decreases as the hydrogen ion concentration increases.

<u>Explanation:</u>

When there is a decrease in pH, that is pH decreases from 6 to 3 then the acidity increases.

That is the pH is between 1 to 7 then it is acidic

When the pH is 7 then it is neutral

When the pH is between  7 to 14 then it is basic

As the H⁺ ion concentration increases, then the pH value decreases, here pH decreases from 6 to 3.

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3 0
3 years ago
Find the number of moles of argon in 364 grams of argon.
serg [7]

Answer:D. 9.1 mole Ar

Explanation:

364 g Ar x 1 mole Ar / 40 g Ar

= 9.1 moles Ar

3 0
3 years ago
Calculate the mass of aluminum in 500 g of Al(C2H3O2)3
Luden [163]
Answer: 66.2 g

Explanation:

1) The ratio of Al in the molecule is  1 mol to 1 mol .

2) The mass of 1 mol of molecules of Al (CH2H3O2)3 is the molar mass of the compound.

3) You calculate the molar mass of the compound using the atomic masses of each atom, in this way:

Al: 27 g/mol
C: 2 * 3 * 12 g/mol = 72 g/mol
H: 3 * 3 * 1 g/mol = 9 g/mol
O: 2 * 3 * 16 g/mol = 96 g/mol

Molar mass = 27 g/mol + 72 g/mol + 9 g/mol + 96 g/mol = 204 g/mol

4) Set a proportion:

    27 g/mol                x
-------------------- =  ----------
   204 g/mol            500 g

5) Solve for x:

x = 500 g * 27 g/mol / 204 g/mol = 66.2 g
5 0
3 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
x:=5.8* 16/84 
this is approximately 1.1
4 0
3 years ago
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