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Savatey [412]
3 years ago
5

A recently depolarized area of a cell membrane cannot generate an action potential because of the

Chemistry
2 answers:
Ann [662]3 years ago
8 0
It can not generate an action potential because of the absolute refractory period.
marysya [2.9K]3 years ago
4 0
The refractory period makes the cell rest. In this period, the cell becomes able to depolarize again by collecting ions.
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When atmospheric carbon dioxide reacts with water in the atmosphere, it forms carbonic acid. This acid can then react with some
Nastasia [14]

Answer:

The terms used to describe the given process in <em><u>Chemical weathering.</u></em>

Explanation:

Weathering of rock is defined as breaking down of the rock into small pieces.

There are two types pf weathering :

Mechanical weathering : This weathering is due to change in physical parameters : temperature change, pressure change etc.

For example : When water soaked up in cracks or crevices of rocks freezes it expands and physically breaks the rock.

Chemical weathering : This weathering is decomposition of rocks due to action of chemicals.This type of weathering also changes chemical composition of rocks.

For example : when gases like carbon dioxide, sulfur oxide get dissolves in water present in rock to form weak acid which ease up the dissolving of rock in that weak acid.

6 0
4 years ago
the equilibrium concentrations were found to be [H2O]=0.250 M , [H2]=0.600 M , and [O2]=0.800 M . What is the equilibrium consta
antoniya [11.8K]

Answer:

Keq = 0.217

Explanation:

Let's determine the equilibrium reaction.

In gaseous state, water vapor can be decomposed to hydrogen and oxygen and this is a reversible reaction.

2H₂(g)  + O₂(g)  ⇄  2H₂O (g)         Keq

Let's make the expression for the equilibrium constant

Products / Reactants

We elevate the concentrations, to the stoichiometry coefficients.

Keq = [H₂O]² / [O₂] . [H₂]²

Keq = 0.250² / 0.8 . 0.6² =  0.217

3 0
3 years ago
How many atoms of argon occupy 30.0L
Airida [17]
5.18mL i hope this helps i hope this does to!
6 0
3 years ago
A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s
s344n2d4d5 [400]
We first calculate the heat released:
Specific heat = 3.21 kJ/kgK
Heat released = heat absorbed by calorimeter
Heat absorbed = mcΔT
= 1.9 x 3.21 x 4.542
= 27.7 kJ

Now, we calculate the moles of hexane present:
Moles = mass / Mr
moles = 0.58 / (12 x 6 + 14)
= 0.0067

Heat of combustion = 27.7 / 0.0067 kJ/mol

ΔH(combustion) = 4,134.3 kJ / mol

8 0
3 years ago
Read 2 more answers
Please help I need help:(((​
Elza [17]

Answer:

I am not understand bro a question

7 0
3 years ago
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