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Savatey [412]
3 years ago
5

A recently depolarized area of a cell membrane cannot generate an action potential because of the

Chemistry
2 answers:
Ann [662]3 years ago
8 0
It can not generate an action potential because of the absolute refractory period.
marysya [2.9K]3 years ago
4 0
The refractory period makes the cell rest. In this period, the cell becomes able to depolarize again by collecting ions.
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What greek letter are used in the precise definition of a limit?
Ivan
Epsilon-delta would be the green letter that is used in the precision definition of a limit. (ε, δ).
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3 years ago
Help please! -A compound contains 0.013 moles of carbon, 0.039 moles of hydrogen and 0.0065 moles of oxygen. Determine the empir
stepan [7]

A) C2H6O1

To find the emperical formula, divide each mole value by the smallest

For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Emperical formula = C2H6O1

8 0
3 years ago
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wolverine [178]
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If you have 177 grams of C4H80, how many moles do you have?
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3 years ago
Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i
Goshia [24]

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and 3.073\times 10^4kJ/L respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

\Delta H^o_{comb}=-3535kJ/mol

Fuel value = \frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}

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Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = 3.073\times 10^4kJ/L

Thus, the fuel density of pentane is 3.073\times 10^4kJ/L

4 0
3 years ago
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