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3 years ago

Acetone is a three-carbon aldehyde. True/False.

Chemistry

1 answer:

stiv31 [10]3 years ago

5 0

Answer: acetone is a ketone and not an aldehyde. Therefore it's false

Explanation:

Acetone is of structure CH3-CO-CH3

which makes it a ketone.

Both aldehyde and ketone have a carbonyl group but there is difference between aldehyde and ketone.

Aldehydes have a general formula R-CHO

where R is a methyl group including H atom, and CHO is the functional group.

While

Ketone have the general formula R-CO-Ri

where R and Ri are methyl groups excluding H atom, and CO is the functional group.

Hint: ketones usually end with the suffix "one" as in acetone.

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Elodia [21]

D- Rusting car fender

4 0

3 years ago

Read 2 more answers

How many liters of space will 7.80 moles of methane gas (CH4) occupy at STP

Alchen [17]

Answer:

V CH4(g) = 190.6 L

Explanation:

assuming ideal gas:

PV = RTn

∴ STP: T =298 K and P = 1 atm

∴ R = 0.082 atm.L/K.mol

∴ moles (n) = 7.80 mol CH4(g)

∴ Volume CH4(g) = ?

⇒ V = RTn/P

⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)

⇒ V CH4(g) = 190.6 L

4 0

3 years ago

3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic e

mezya [45]

Answer: Hydrogen molecules will have greatest average speed.

Explanation:

The formula for average speed is :

$\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}$

R = gas constant

T = temperature

M = Molecular Mass

Now putting all the values:

$\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}$

$\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}$

$\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8$

Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed

8 0

2 years ago

Catalyst

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

3 years ago

How many liters of water vapor are in 36.21 g?

Elden [556K]

Answer:

45.02 L.

Explanation:

Firstly, we need to calculate the no. of moles of water vapor.

n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.

We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

<em><u>Using cross multiplication:</u></em>

1.0 mole of CO occupies → 22.4 L.

2.01 mole of CO occupies → ??? L.

∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.

4 0

3 years ago