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soldi70 [24.7K]
3 years ago
8

Acetone is a three-carbon aldehyde. True/False.

Chemistry
1 answer:
stiv31 [10]3 years ago
5 0

Answer: acetone is a ketone and not an aldehyde. Therefore it's false

Explanation:

Acetone is of structure CH3-CO-CH3

which makes it a ketone.

Both aldehyde and ketone have a carbonyl group but there is difference between aldehyde and ketone.

Aldehydes have a general formula R-CHO

where R is a methyl group including H atom, and CHO is the functional group.

While

Ketone have the general formula R-CO-Ri

where R and Ri are methyl groups excluding H atom, and CO is the functional group.

Hint: ketones usually end with the suffix "one" as in acetone.

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Question 1(Multiple Choice Worth 4 points) (04.05 LC) What is the oxidation number of manganese in MnO41−? +3 +4 +7 +8 Question
Elan Coil [88]

1) Answer is: the oxidation number of manganese in MnO₄⁻ is +7.

Permanganate anion has negative charge 1-.

Oxygen (O) in permanganate anion has oxidation number -2.

x + 4 · (-2) = -1.

x - 8 = -1.

x = +7; oxidation nzmber of manganese.

Oxidation number shows the degree of oxidation of an atom in a chemical compound.

2) Answer is: Zn + Cu2+ → Zn2+ + Cu.

In this chemical reaction, there is transfer of electrons from zinc (Zn) to copper (Cu). Zinc change oxidation number from 0 to +2 (lost electrons) and copper change oxidation number from +2 to 0 (gain electrons).

Oxidation half reaction: Zn⁰ → Zn²⁺ + 2e⁻.

Reduction half reaction: Cu²⁺ + 2e⁻ → Cu⁰.

In other chemical reactions, there is no change of oxidation number of elements.

3) Answer is: Br2 is the oxidizing agent because its oxidation number decreases.

Balanced chemical reaction: 2Al + 3Br₂ → 2AlBr₃.

In this chemical reaction, aluminium change oxidation number from 0 to +3 (lose electrons) and bromine change oxidation number from 0 to -1 (gain electrons, reduced).

Oxidizing agent is a substance that has the ability to oxidize other substances, to cause them to lose electrons.

In oxido-reduction reaction, at least one element lose and one element gain electrons.

4) Answer is: Br2 + 2Cl− → Cl2 + 2Br⁻.

Oxidation is increase of oxidation number.

In this balanced chemical reaction, chlorine change oxidation number from -1 (Cl⁻) to oxidation number 0 (Cl₂).

Oxidation half reaction: 2Cl⁻ → Cl₂⁰ + 2e⁻.

Reduction half reaction: Br₂ + 2e⁻ → 2Br⁻.

In other chemical reactions, chlorine is reduced.

5) Answer is: Observation 1 is a result of copper ions moving into the solution.

The reactivity series is a series of metals from highest to lowest reactivity. Metal higher in the reactivity series will displace another.

Copper (Cu) is higher in activity series than silver (Ag), so copper lose electron and silver gain electrons.

Copper is oxidized (increase of oxidation number) and silver is reduced.

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2 years ago
What type of reaction is pb(no3)2(aq) + 2kcl(aq) ® pbcl2(s) + 2kno3(aq)?
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The given reaction is,

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White gold is an alloy that typically contains 60.0% by mass gold and the remainder is platinum. if 175 g of gold are available,
weeeeeb [17]
If a sample of white gold alloy contains 60 percent by mass of gold while the remaining is platinum, then the alloy would contain 40 percent by mass of platinum. <span>Percentage by mass is the amount in mass units of a component in a mixture per 100 unit if mass of the total mixture. We are given the amount of gold available, this represents the 60 percent of the alloy. We calculate for the amount of platinum needed as follows:

Percent of platinum = mass of platinum / mass of gold + mass of platinum
0.40 = mass of platinum / 175 g + mass of platinum
mass of platinum = 117 g</span>
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