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Natasha2012 [34]
3 years ago
10

A 25.00 mL aliquot of concentrated hydrochloric acid (11.7M) is added to 175.00 mL of 3.25M hydrochloric acid. Determine the num

ber of moles of hydrochloric acid from 175.00 mL of 3.25 M hydrochloric acid solution.
Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
5 0

Answer:

The number of moles of hydrochloric acid are 0.861

Explanation:

In first solution, the [HCl] is 11.7 M, which it means that 11.7 moles are present in 1 liter.

So we took 25 mL and we have to know how many moles, do we have now.

1000 mL ____ 11.7 moles

25 mL _____ (25 . 11.7)/1000 = 0.2925 moles

This are the moles, we add to the solution where the [HCl] is 3.25 M

In 1000 mL __ we have __ 3.25moles

175 mL ____ we have __ (175 . 3.25)/1000 = 0.56875 moles

Total moles: 0.2925 + 0.56875 = 0.861 moles

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In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

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