Answer:
740, mm of Hg
Explanation:
The pressure of argon , in mm of Hg = difference in the level of mercury on either side of the manometer.
mercury column in the open end of the manometer is 22 mm below that in the side connected to the argon and 762 mmHg, end is open to atmospheric pressure.
therefore, The pressure of argon , in mm of Hg =762 -22 = 740, mm of Hg
Answer:
8000 kg/cm^3
Explanation:
The density formula is P = M/V
Density = P = ? expressed in kg/m^3
M = mass = 40,000 kg
V = volume = 5 m^3
P = 40,000/5
P = 8000 kg/m^3
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :
F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :
P = 0.202 Pa
Hence, this is the required solution.
I think it is false, because why would is be stronger in a different state?
C. air above the wing travels faster than air below the wing.
