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olasank [31]
3 years ago
5

Two resistors are used in an experiment. Resistor 1 had a resistance of 4 ohms and resistor 2 has a resistance of 2 ohms. Which

resistor will have the bigger current flowing through it if the potential difference is constant
Physics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

2ohms resistor

Explanation:

According to ohms law

V= IR

V is the potential difference

I is the current

R is the resistance

Since they have the same potential difference, this shows that they are connected in parallel

Let assume V = 20V

For the 4ohms resistor

I = V/R

I = 20/4

I = 5A

For the two ohms resistor

I = V/R

I = 20/2

I = 10A

This shows that the 2ohms resistor will have the bigger current because the smaller the load, the bigger the current and vice versa

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3 years ago
Read 2 more answers
A square loop of side 7 cm is placed with the nearest side 2 cm from a long wire carrying a current that varies with time at a c
ioda

Answer:

Explanation:

side of the square loop, a = 7 cm

distance of the nearest side from long wire, r = 2 cm = 0.02 m

di/dt = 9 A/s

Integrate on both the sides

\int _{0}^{i}di =9\int _{0}^{t}dt

i = 9t

(a) The magnetic field due to the current carrying wire at a distance r is given by

B = \frac{\mu_{0}i}{2\pi r}

B = \frac{\mu_{0}\times 9t}{2\pi r}

(b)

Magnetic flux,

\phi=\int B\times a dr

\phi=\int \frac{\mu_{0}\times 9t}{2\pi r}\times a dr

\phi=\frac{\mu_{0}\times 9t\times a}{2\pi}\times ln\left ( \frac{2 + 7}{2} \right )

\phi=\frac{\mu_{0}\times 9t\times 0.07}{2\pi}\times ln(4.5)

\phi = 1.89 \times 10^{-7}t

(c)

R = 3 ohm

e = -\frac{d\phi}{dt}

magnitude of voltage is

e = 1.89 x 10^-7 V

induced current, i = e / R = (1.89 x 10^-7) / 3

i = 6.3 x 10^-8 A

8 0
3 years ago
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