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olasank [31]
3 years ago
5

Two resistors are used in an experiment. Resistor 1 had a resistance of 4 ohms and resistor 2 has a resistance of 2 ohms. Which

resistor will have the bigger current flowing through it if the potential difference is constant
Physics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

2ohms resistor

Explanation:

According to ohms law

V= IR

V is the potential difference

I is the current

R is the resistance

Since they have the same potential difference, this shows that they are connected in parallel

Let assume V = 20V

For the 4ohms resistor

I = V/R

I = 20/4

I = 5A

For the two ohms resistor

I = V/R

I = 20/2

I = 10A

This shows that the 2ohms resistor will have the bigger current because the smaller the load, the bigger the current and vice versa

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Draw the following vector quantity Using the coordinate system.
DiKsa [7]

The given vectors quantities can be described by their properties of both

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  • a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.
  • b. The velocity vector extending from  (0, 0) to (108.76, 50.714) on the coordinate plane is attached.
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Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

\vec{F} = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; \vec{v} = 120 × cos(25)·i + 120×sin(25)·j, which gives;

\vec{v} = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

\vec{v} ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is \vec{d} = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

\vec{d} = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

Learn more about vectors here:

brainly.com/question/10409036

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