The correct answer is Three. Solving the given expression we get,
2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) = 1364.47÷ (6.85 × 103 g) = 1364.47÷ 705.55 = 1.93
Here, the number of significant figures is three. Thus, the result should have three <span>significant figures.</span>
6.023*1023 He atoms=1 mole He
1.23×1024 helium atoms=1.23×1024/6.023*1023 =2.042 mole He
one mole He=4.0 gm
2.042 mole He=2.042*4.0=8.168 gm
answer in grams of Helium is 8.168 gm
The reaction is
Cu⁺²(aq) ---> Cu(s) [reduction]
The species which undergoes reduction is able to oxidize other one thus will called as "oxidizing agent"
Thus Cu⁺² is an oxidizing agent
or Cu is a reducing agent
Al(s) ---> Al⁺³(aq)
Aluminium is undergoing oxidation
Thus is able to reduced others and hence is a reducing agent
Al is a reducing agent
or Al⁺³ is an oxidizing agent
Answer: Cu is the reducing agent, and AI3+ is the oxidizing agent.
Answer:
<h2>

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Explanation:
According to hooks law "provide the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force F"

where F= applied force
k= spring constant
e= extension
Given data
length of string l = 16cm
extension e = 20-16= 4cm
applied force = 5N
we need t o first calculate the spring constant k
apply the formula


we can now calculate the extension of the string when supporting a 6N weight

The length of the string when supporting a 6N weight is

<em>COMMENT </em><em>:According to the analysis an extra weight of 1N will cause add 0.8cm to the length of the string</em>
There are 24 molecules idk it maybe right