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Gekata [30.6K]
2 years ago
5

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation

Chemistry
1 answer:
Arte-miy333 [17]2 years ago
7 0

Answer:

We need 67.2 grams of 02. There  will be produced 92.421 grams of CO2

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6 (aq) + 6O2 (g) = 6CO2 (g) + 6H2O (l)

<u>Step 2</u>: Data given

We can see that for 1 mole C6H12O6 consumed, we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O

The mass of glucose is 63.0g

The molar mass of glucose is 180.156 g/mole

The molar mass of O2 is 32 g/mole

The molar mass of CO2 is 44.01 g/mole

<u>Step 3: </u>Calculate number of moles of glucose

Number of moles of glucose = mass of glucose / molar mass of glucose

Number of moles of glucose = 63 grams /180.156 g/moles = 0.35 moles

<u>Step 4:</u> Calculate number of moles of oxygen ( and CO2)

For 1 mole of glucose we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O

So for 0.35 moles of glucose we need 6*0.35 = 2.1 moles of O2 to produce 2.1 moles of CO2 and 2.1 moles of H2O

<u>Step 5:</u> Calculate mass of oxygen ( and CO2)

mass of oxygen = number of moles of oxygen * Molar mass of oxygen

mass of oxygen = 2.1 moles * 32 g/mole = 67.2 g O2 (≈ 67 grams)

mass of CO2 = number of moles of CO2 * Molar mass of CO2

mass of CO2 = 2.1 moles * 44.01 g/mole = 92.421 grams

We need 67.2 grams of 02. There  will be produced 92.421 grams of CO2

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Answer:

490 in^3 = 8.03 L

Explanation:

Given:

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To determine the engine piston displacement in liters L;

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First, we will convert in³ to cm³

Since 1 in = 2.54 cm

∴ 1 in³ = 16.387 cm³

If 1 in³ = 16.387 cm³

Then 490 in³ =  (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³

∴ 490 in³ = 8029.63 cm³

Now will convert cm³ to dm³

(NOTE: 1 L = 1 dm³)

1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm

∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³

If 1 cm³ = 1 × 10⁻³ dm³

Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³

≅ 8.03 dm³

∴ 8029.63 cm³ = 8.03 dm³

Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³

Since 1L = 1 dm³

∴ 8.03 dm³ = 8.03 L

Hence, 490 in³ = 8.03 L

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The equation X + Y yields 
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How many atoms and elements are there in C2H5OH
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Explanation:

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B. sodium cyanide =NaCN

C. Magnesium nitrate = Mg(NO3)2

D. Barium sulfate = BaSO4

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te
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Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

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Therefore,

pH = 7.21 + log (0.663 / 0.096)

pH = 7.21 + 0.84

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