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Vsevolod [243]
3 years ago
6

On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per

hour and drive for an additional two hours.Required:a. How far do you go?b. What is your average x component of velocity?c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour?
Physics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

A.) 230 km

B.) 76.67 km/h

Explanation:

Given that On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per hour and drive for an additional two hours.

A.) How far do you go?

When driving for an hour, the distance covered will be

Distance = speed × time

Distance = 50 × 1 = 50 km

When driving for additional 2 hours, the distance covered will be

Distance = 90 × 2 = 180 km

Total distance = 180 + 50 = 230 km

b. What is your average x component of velocity?

Average Velocity = total distance/ total time

Average velocity = 230/3

Average velocity = 76.67 km/h

c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour

They are not equal because of the displacement is the same as distance travelled.

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Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.
Gnoma [55]

Answer:

1.5 \Omega

Explanation:

The resistance of a wire is given by:

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

For the wire in this problem:

\rho = 3.3\cdot 10^{-7} \Omega m

L = 7.0 m

r = d/2 = 0.07 cm = 0.0007 m, so the area is

A=\pi r^2=\pi(0.0007)^2=1.54\cdot 10^{-6}m^2

Solving for R,

R=\frac{(3.3\cdot 10^{-7})(7.0)}{1.54\cdot 10^{-6}}=1.5 \Omega

8 0
3 years ago
8. If a circuit has a current of 25.4 amps with 12.6
grin007 [14]

The resistance of the circuit is 0.496 \Omega

Explanation:

We can solve the problem by applying Ohm's law, which gives us the relationship between current, potential difference and resistance in a circuit:

V=RI

where

V is the potential difference

R is the resistance

I is the current

For the circuit in this problem,

V = 12.6 V

I = 25.4 A

Re-arranging the equation, we can solve for the resistance:

R=\frac{V}{I}=\frac{12.6}{25.4}=0.496 \Omega

Learn more about current and potential difference here:

brainly.com/question/4438943

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#LearnwithBrainly

8 0
4 years ago
An antibaryon composed of two antiup quarks
Sveta_85 [38]

Answer:

(2) −1 e

Explanation:

A quark is the lightest elementary particles which form hadron such as proton and neutron. A quark has fractional charge.

Up, charm and top quarks have +\frac{2}{3} e charge where as down, strange and bottom quarks have -\frac{1}{3}e charge.

The antiparticle of up quark is antiup quark and has charge -\frac{2}{3}e charge.

The antiparticle of down quark is antidown quark and has charge +\frac{1}{3}e charge.

An antibaryon is composed of two anti-up quark and one anti-down quark.

Net charge of the anti-baryon is:

2\times (-\frac{2}{3} e)+1\times (+\frac{1}{3})e=-1e

Thus, antibaryon has -1e charge.

5 0
4 years ago
Can someone please help for a , what am I meant to do
monitta
I’m not sure what your question is but I hope I can be of help. Series would split voltage and have same current all through, whereas parallel would have the same voltage all throughout but would have different amperes(currents)
8 0
3 years ago
Determine the kinetic energy of a girl of mass 40kg running with a velocity of 3m/s
kotegsom [21]
0.5mv^2
0.5 times 40 times 3^2
The kinetic energy is 180
4 0
3 years ago
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