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slamgirl [31]
3 years ago
7

5. If all the particles in a material are made up of

Chemistry
1 answer:
mel-nik [20]3 years ago
4 0

If all the particles in a material are made up of

several smaller particles, and every larger particle

is identical, is the material a pure substance or

not? Explain your reasoning.

A pure substance is something like a compound and element. This material made of several particles which seem to be two different particles, I believe, is a mixture. So, it is not a pure substance mixtures are made up of more than one particle while compounds (In a fixed ratio, the fusion of two or more than two atoms) and elements are made up of one molecule essentially.

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Which is the correct formula for phosphorus pentachloride?
klio [65]

PCl5

hope this helps

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2 years ago
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Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants t
solmaris [256]

Answer:

he can bang metal pipes but i would rather say that he has to yell for help

Explanation:

why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out

hope this helped

4 0
3 years ago
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As an electron gains energy, it becomes excited and jumps to a lower energy level?
Maru [420]

Yes if you add an energy to an electron the electron will become excited, and it will jump to its highest level then go back down releasing  energy


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2 years ago
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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
2 years ago
Draw the structural formula for fatty acid C 18:2 9 a 12a
qwelly [4]

Answer:

............................................................................

Explanation:

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