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IRINA_888 [86]
3 years ago
12

The higher the hydronium ion concentration of a solution, the ____ its pH.

Chemistry
2 answers:
pickupchik [31]3 years ago
6 0

Answer:

B. Lower

Explanation:

Remember that the pH is calculated as

-log (H30 +)

That is, at a higher concentration of H30 +, with the -log, the pH value decreases and vice versa.

With a concentration 1e-5, it yields a pH of 5.00 and with 1e-2 a value of 2.00

Vilka [71]3 years ago
5 0

Answer:

Explanation:

The hydronium ion is [H3O+] or it can be written as [H+].[H2O].

As pH is a measure of the concentration of [H+], pH = -log[H+].

The higher the hydronium ion concentration of a solution, the _<u>Lower</u>_ its pH.

The answer is B.

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Because potassium is a gas that can evolve
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Do you think a colony on Mars should be nearer the northern or southern<br> polar cap? Explain.
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Answer:

nearer to the north pole

Explanation:

because there is more water, which is basically gone everywhere else on Mars except for the south pole which has less water than the north pole

7 0
3 years ago
a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu
Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

3 0
3 years ago
Which element has the highest ionization energy<br> A. Calcium<br> B. Bromine<br> C. Astatine
inessss [21]

Answer:

bromine

Explanation:

4 0
3 years ago
Read 2 more answers
In boyle's law, the initial volume of a gas is 120 ml at 256 kpa. what will be the volume if the pressure increases to 385 kpa?
Vinil7 [7]
<h3>Answer:</h3>

79.8 ml

<h3>Explanation:</h3>

Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.

Boyle's Formula

When describing the relationship between pressure and volume, the formula \displaystyle P_{1} V_{1}= P_{2} V_{2}. In this formula, P_{1}V_{1} is the initial pressure and volume. On the other side, P_{2} V_{2} is final pressure and volume. So, to find a missing variable you must plug in the values you are given.

Final Volume

Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:

  • 256kPa*120mL=385kPa*V_{2} mL

Now, we can multiply the left side

  • 30720kPa*mL=385kPa*V_{2} mL

Finally, we can divide by 385 to isolate the final volume

  • 79.8mL=V_{2}

This gives the final volume of 79.8mL.

7 0
2 years ago
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