Answer:
110 rev
Explanation:
Given:
v₀ = 32 m/s
v = 0 m/s
a = -2.25 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (32 m/s)² + 2 (-2.25 m/s²) Δx
Δx = 228 m
The circumference of the tires is 2π × 0.32 m = 2.01 m. Therefore:
228 m × (1 rev / 2.01 m) = 110 rev
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In re-action, a thrusting force is produced on the engine mount. The thrust accelerates the rocket as described by Newton's second law of motion.
Explanation:
Answer:
the road has a larger coefficient of linear expansion than the dirt
Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is 1.3 atm.
From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;
PT = PA + PB + PC + --------
Given that;
Vapor pressure of oxygen = 0.2 atm
Total pressure = 1.5 atm
Vapor pressure of oxygen = ?
Partial pressure of oxygen = 1.5 atm - 0.2 atm = 1.3 atm
The vapor pressure of oxygen is 1.3 atm.
Learn more: brainly.com/question/2510654
KE=1/2mv^2
So the 3kg ball rolling at velocity of 3m/s has a KE=1/2(3)(3^2)=27/2=13.5J
The 2kg ball only has a KE=1/2(2)(3^2)=9J
So we can see the 3kg ball has more KE than the 2kg ball because they are moving at the same velocity so the bigger mass has more KE