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3 years ago

5

Relating to Newton’s Third Law, action and reaction, what is the reaction when a rocket expels gas, smoke and flames from the no

zzle end of the rocket engine?

1 answer:

Cloud [144]3 years ago

7 0

Answer:

Propels in the opposite direction

Explanation:

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A linebacker strikes a fullback with full force in a football game.The reaction force to the force of the linebacker striking th

Scrat [10]

A. the back falls backwards to the ground

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3 years ago

In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.

Zanzabum

Https://www.cymath.com/answer?q=%205%2B4i%2F6%2B8i
this site can help you

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3 years ago

Read 2 more answers

Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d

alex41 [277]

Answer:

$v=18.89\frac{m}{s}$

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

$\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)$

Solving N from (2) and replacing in (1):

$N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c$

The centripetal acceleration is given by:

$a_c=\frac{v^2}{r}$

Replacing and solving for v:

$gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}$

4 0

4 years ago

A ball is dropped from a height of 1m. If the coefficient of restitution between the ball and the surface is 0.6, what is the he

gtnhenbr [62]

Answer:

0.7

Explanation:

1 + 0.6 = 0.7 I think

hope this helps

7 0

3 years ago

A tennis player hits a ball at an angle of 50 degrees above horizontal so that it has an acceleration of 12 m/s2. What is the ho

harkovskaia [24]

So we want to know what is the magnitude of the horizontal component of acceleration ah if we know that the overall acceleration a=12 m/s^2 and the angle of overall acceleration and the horizontal acceleration is α=50°. We know that ah=a*cosα. So now it isn't hard to get the horizontal component: ah=12*cos50=12*0.64=7.71 m/s^2. So the correct answer is ah=7.71 m/s^2.

6 0

3 years ago