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2 years ago

What elements are not a major category of elements on the periodic table

Physics

1 answer:

lana66690 [7]2 years ago

3 0

Answer:

Group and Periods of the Periodic Table of Elements. The three major groups on the Periodic Table are the metals, nonmetals and metalloids. Elements within each group have similar physical and chemical properties.

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The Milky Way is our Galax. Where are we located in Milky Way?

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Earth is located in one of the spiral arms of the Milky Way (called the Orion Arm) which lies about two-thirds of the way out from the center of the Galaxy.

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3 years ago

What happens to the equilibrium price and quantity for jelly when the price of peanut butter increases? (Assume that peanut butt

Darya [45]

Answer:

Equilibrium price will fall and quantity demanded for jelly will also fall

<u>Explanation:</u>

Peanut butter and jelly are consumed together. It means they are complementary goods. These are those goods which are bought together. So increase or decrease in the price of one commodity will automatically affect the demand for another commodity.

When the price of peanut butter increases than people will demand less of peanut butter. Similarly, the demand for jelly is associated directly with the demand for peanut butter. So it will also fall . Due to the fall in the price of jelly and simultaneous fall in demand, the equilibrium price will fall.

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3 years ago

What do all elements in a column in the periodic table have in common?

JulsSmile [24]

Answer:

1, their atoms have the same number of valence electron. because valence electron determine the group of elements.

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3 years ago

Why are latitude and longitude included on maps

Veseljchak [2.6K]

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2 years ago

Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10

gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

$\Sigma \tau=0$

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

$-\tau_l+\tau_p+\tau_{cm}=0$ (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

$\tau=Fd$ (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

$-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N$

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

$F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N$

The force applied by the left support is 2123.33 N

8 0

3 years ago