Answer: Objects falling through a fluid eventually reach terminal velocity. At terminal velocity, the object moves at a steady speed in a constant direction because the resultant force acting on it is zero.
The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed by an object can be calculated by using the following expression:
Where;
- Q = amount of heat absorbed or released (J)
- m = mass of object
- c = specific heat capacity (J/g°C)
- ∆T = change in temperature (°C)
- According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:
- Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.
Learn more about how to calculate heat absorbed at: brainly.com/question/11194034?referrer=searchResults
Answer:
The force will be 
Explanation:
Let's use the centripetal force equation.
Where:
m is the mass of the bunch of bananas
ω is the angular speed
R is the radius
Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.
FInally, the force will be:
I hope it helps you!
Answer:
4.32
Explanation:
The centripetal acceleration of any object is given as
A(cr) = v²/r, where
A(c) = the centripetal acceleration
v = the linear acceleration
r = the given radius, 1.9 m
Since we are not given directly the centripetal acceleration, we'd be using the value of acceleration due to gravity, 9.8. This means that
9.8 = v²/1.9
v² = 1.9 * 9.8
v² = 18.62
v = √18.62
v = 4.32 m/s
This means that, the minimum speed the cup must have so as not to get wet or any spill is 4.32 m/s
