Burning a log because you are turning the log into ash from wood.
Answer:
35 revolutions
Explanation:
t = Time taken
= Final angular velocity
= Initial angular velocity
= Angular acceleration
= Number of rotation
Equation of rotational motion
![\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Calpha%20t%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B%5Comega_f-%5Comega_i%7D%7Bt%7D%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B3-0%7D%7B10.7%7D%5C%5C%5CRightarrow%20%5Calpha%3D0.28037%5C%20rev%2Fs%5E2)
![\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev](https://tex.z-dn.net/?f=%5Comega_f%5E2-%5Comega_i%5E2%3D2%5Calpha%20%5Ctheta%5C%5C%5CRightarrow%20%5Ctheta%3D%5Cfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Calpha%7D%5C%5C%5CRightarrow%20%5Ctheta%3D%5Cfrac%7B3.1%5E2-0%5E2%7D%7B2%5Ctimes%200.28037%7D%5C%5C%5CRightarrow%20%5Ctheta%3D17.13806%5C%20rev)
Number of revolutions in the 10.7 seconds is 17.13806
![\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Calpha%20t%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B%5Comega_f-%5Comega_i%7D%7Bt%7D%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B0-3.1%7D%7B11.2%7D%5C%5C%5CRightarrow%20a%3D-0.27678%5C%20rev%2Fs%5E2)
![\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev](https://tex.z-dn.net/?f=%5Comega_f%5E2-%5Comega_i%5E2%3D2%5Calpha%20%5Ctheta%5C%5C%5CRightarrow%20%5Ctheta%3D%5Cfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Calpha%7D%5C%5C%5CRightarrow%20%5Ctheta%3D%5Cfrac%7B0%5E2-3.1%5E2%7D%7B2%5Ctimes%20-0.27678%7D%5C%5C%5CRightarrow%20%5Ctheta%3D17.36035%5C%20rev)
Number of revolutions in the 11.2 seconds is 17.36035
Total total number of revolutions in the 21.9 second interval is 17.13806+17.36035 = 34.49841 = 35 revolutions
Answer:
estivation is my answer.
Explanation:
Hibernation and estivation are similar, but hibernation takes place during cold months.
Estivation during summer months, the amphibian becomes dormant during this time.
The eagle would have more momentum. The formula for momentum is mass times velocity, and since the eagle has a significantly greater mass, its momentum would also be greater.
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