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notka56 [123]
3 years ago
7

If a box is pushed 5.0 m across a floor using a force of 35 N, how much work was done?

Physics
1 answer:
aniked [119]3 years ago
3 0

Answer:

175J

Explanation:

Work done is given by the product of the force applied and the distance travelled as a result of that force.

Or in formula , W=F×d

Thus,

W= 35 × 5.0=175 J or 1.8 e2 J

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The surface tension of isopropanol in air has a value of 23.00 units and the
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Please help me guys never mind the calculations ​
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The shape is connected in parallel so;

5.1) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  \\  \frac{1}{R}  =  \frac{3 + 2}{6}  =  \frac{5}{6}  \\ R =  \frac{6}{5}  = 1.2 \:  \: ohm

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Sound wave A has a lower frequency than sound wave B, but both waves
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Answer:

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Explanation:

In order to solve this problem, we can do an analysis of the energies involved in the system. Basically the addition of the initial potential energy of the spring and the kinetic energy of the mass should be the same as the addition of the final potential energy of the spring and the kinetic energy of the block. So we get the following equation:

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U_{0}=K_{f}

The initial potential energy of the spring is given by the equation:

U_{0}=\frac{1}{2}kd^{2}

the Kinetic energy of the block is then given by the equation:

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so we can now set them both equal to each other, so we get:

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This new equation can be simplified if we multiplied both sides of the equation by a 2, so we get:

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