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Yakvenalex [24]
3 years ago
7

Los estudiantes de la clase del Sr. Malio trabajaron en una investigación para medir el tiempo que le tomó al automóvil de energ

ía viajar a diferentes posiciones en una pista recta y nivelada. Usando sus datos, dibujaron el gráfico de posición versus tiempo que se muestra arriba. Utilice este gráfico para responder las siguientes preguntas.
Por favor ayúdenme necesito que me respondan rápido
Physics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

5

Explanation:

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Which statement best describes a characteristic of gases?
salantis [7]
Assumes the shape and volume of its container 
<span>particles can move past one another</span>
8 0
3 years ago
James gently releases a ball at the top of a slope But does not push the ball. Space the ball rolls down the slope. Which force
NARA [144]
On an incline, the force causing the ball to move downwards would be gravity. Additionally, the component of gravity causing this ball to move downwards would be mgsintheta.

Hope this helps!
7 0
3 years ago
Read 2 more answers
A physicist makes a cup of instant coffee and notices that, as the coffee cools, its level drops 3.00 mm in the glass cup. Show
Lady bird [3.3K]

Answer:

change in height  is 1.664 mm

Explanation:

Given data

drops = 3.00 mm

diameter = 5.00 cm = 0.05 mm

decrease  =  350 cm^3

temperature = 95°C to 44.0°C

to find out

the decrease in millimeters in level

solution

we  will calculate here change in volume so we can find how much level is decrease

change in volume = β v change in temp   ...............1

here change in volume = area× height

so = \pi /4 × d² h

so we can say change in volume =  \pi /4 × d² × change in height   .......2

so from equation 1 and 2  we calculate change in height

( β(w) -β(g) )× v× change in temp = \pi /4 × d² × change in height

change in height = 4 × ( β(w) -β(g) ) v× change in temp / \pi /4 × d²

put all value here

change in height = 4 × ( 210 - 27 )(350 ) 10^{-6}× (95-44) / \pi /4 × 0.05²

change in height  is 1.664 mm

5 0
3 years ago
A sprinter generates a constant force of 52 N as he runs 100 m. How much work did he do?
LUCKY_DIMON [66]
You just multiply these two numbers. It's 5200J, or 5.2kJ
3 0
4 years ago
A charged particle A exerts a force of 2.45 μN to the right on charged particle B when the particles are 12.2 mm apart. Particle
Brilliant_brown [7]

Answer:

F_2 = 1.10 \mu N

Explanation:

As we know that the electrostatic force is a based upon inverse square law

so we have

F = \frac{kq_1q_2}{r^2}

now since it depends inverse on the square of the distance so we can say

\frac{F_1}{F_2} = \frac{r_2^2}{r_1^2}

now we know that

r_2 = 18.2 mm

r_1 = 12.2 mm

also we know that

F_1 = 2.45 \mu N

now from above equation we have

F_2 = \frac{r_1^2}{r_2^2} F_1

F_2 = \frac{12.2^2}{18.2^2}(2.45\mu N)

F_2 = 1.10 \mu N

5 0
4 years ago
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