Answer:
Explanation:
The quantity of energy transferred by a force when it is applied to a body and causes that body to move in the direction of the force work.
Nuclear fusion in the core tries to blow the star apart. Gravity holds it together. Whoever designed that system really knew what he was doing. I'm kinda grateful to him.
Answer:
D
friction acts in the opposite direction of motion but does not affect the motion of the object
Answer:
N
N
Explanation:
= 1 A
= 4 A
= distance between the two wire = 5 m
= Force per unit length acting between the two wires
Force per unit length acting between the two wires is given as


N
= distance of each wire from the midpoint = 2.5 m
Magnetic field midway between the two wires is given as



Answer:

Given:
Mass of the polar bear (m) = 6.8 kg
Speed of the polar bear (v) = 5.0 m/s
To Find:
Kinetic energy of the polar bear (KE)
Explanation:
Formula:

Substituting values of m & v in the equation:





Kinetic energy of the polar bear (KE) = 23002.1 J