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coldgirl [10]
3 years ago
13

In which group on the periodic table does the atom pictures belong?

Chemistry
2 answers:
malfutka [58]3 years ago
7 0
D)14 explanation I took the test
Triss [41]3 years ago
4 0

Answer: Group 14

Explanation:

It's a carbon atom with 4 valance electrons.

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Consider an electron placed in a region of space in which the electric potential spatially. The electron is placed at a point wh
loris [4]

Answer:

1.33\cdot 10^7 m/s

Explanation:

For a charged particle accelerated by an electric field, the kinetic energy gained by the particle is equal to the decrease in electric potential energy of the particle; therefore:

K_f-K_i = -q\Delta V

where

K_f is the final kinetic energy

K_i is the initial kinetic energy

q is the charge of the particle

\Delta V is the potential difference

In this problem,

q=-1.6\cdot 10^{-19}C is the charge of the electron

\Delta V=-500 V-(-1000 V)=500 V

The electron starts from rest, so its initial kinetic energy is

K_i=0

Therefore,

K_f=-(-1.6\cdot 10^{-19})(500)=8\cdot 10^{-17}J

We can write the final kinetic energy of the electron as

K_f=\frac{1}{2}mv^2

where

m=9.11\cdot 10^{-31} kg is the electron mass

v is the final speed

And solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(8\cdot 10^{-17})}{9.11\cdot 10^{-31}}}=1.33\cdot 10^7 m/s

5 0
3 years ago
100 POINTS ANSWER HURRY
prisoha [69]
C. Not all mixtures have solutes and solvents
7 0
4 years ago
Read 2 more answers
What is the formula of a compound formed between nitrogen (N) and potassium (K)?
Rina8888 [55]
<span>You need to consider the valences of the two elements. Potassium is +1; nitrogen is -3. To balance the molecule, you need 3 potassium to one nitrogen, or K3N</span>
5 0
4 years ago
Read 2 more answers
What is the value of delta Hrxn for this equation:
Ratling [72]

Answer:

The ΔHrxn for the above equation = 179 kJ/mol

Explanation:

The reaction bond enthalpies are for the reactant;

3 × N-H = 3 × 390 = 1,170 kJ/mol

2 × O=O = 2 × 502 = 1004 kJ/mol

The reaction bond enthalpies are for the product;

3 × N-O = 3 × 201 = 603 kJ/mol

3 × O-H = 3 × 464 = 1,392 kJ/mol

The ΔHrxn for the above equation is therefore;

ΔHrxn = 1,170 + 1,004 - (603 + 1,392) = 179 kJ/mol

6 0
3 years ago
Calculate the [oh−] in a solution with a ph of 12.52.
BaLLatris [955]
PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
6 0
3 years ago
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