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77julia77 [94]
2 years ago
9

Which process begins the formation of sedimentary rock? the movement of sediment the cementation of rock sediment the breakdown

of rock into sediment the buildup of sediment in one location
I will mark Brainlyest and 100 points
Chemistry
1 answer:
max2010maxim [7]2 years ago
5 0

Answer:

C- the breakdown of rock into sediment

Explanation:

Because sedimentary rocks have layers and are made of of those layers which are made up of the breakdown of rock into sediment.

hope this helps:)

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What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters
sukhopar [10]

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Explanation:

At standard temperature and pressure, we have:

P_1 = 1atm

T_1 = 273.15k

V_1 = 3.5L

Outside, we have:

T_2 = 296k

V_2 = 2.0L

Required

Determine the new pressure

Using combined gas law, we have:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

This gives:

\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}

Solve for P_2

P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}

P_2 = \frac{1036}{546.30}

P_2 \approx 1.896 atm

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3 years ago
Which metal can replace another metal in a reaction?
deff fn [24]

Answer:

O A. A metal higher on the activity series list will replace one that is

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3 years ago
Which equation will you use to calculate the volume of a 5.00 liter sample of air at 50°C when it is warmed to 100°C at constant
Alexandra [31]
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3 years ago
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3. How are wind and solar energy better than oil
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Answer:

d

Explanation:

3 0
3 years ago
What is the number of moles of Sodium Chloride (NaCl) that is present in 29.22g sample of it?
Liula [17]
There are 0.5 moles of NaCl present in a 29.22g sample.

to find moles of a compound you would look at the periodic table to find the mass. in this case, the mass of NaCl is 58.44 g/mol. now, you divide the sample mass of 29.22g by 58.44 g/mol. the grams will cancel each other out and you’re left with 0.5 mol in that sample

hope this helps!
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3 years ago
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