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jek_recluse [69]
3 years ago
13

GAMMA RAYS What are some applications of gamma rays? In other words, what can we use them for?

Physics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

Explanation:

Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells. Also, industry (sterilization and disinfection) and the nuclear industry.

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Reactive elements such as alkali metals and halogens are found in nature only as
bonufazy [111]

Compounds

Explanation:

Reactive elements such as alkali metals and halogens are found in nature only as compounds. Such elements are too unstable to remain as stable atoms, therefore they readily combine and form compounds.

  • Compounds are formed when two atoms combines together to share electrons.
  • They either lose, gain, or share electrons between themselves.
  • In the end, they end up becoming more stable.
  • This is the reason why atoms combine.
  • Unstable elements are very reactive especially alkali metals and halogens.
  • On their own, they are unstable and prefers to bond with other atoms in order to gain a measure of stability.
  • This is why they are found in combined state in nature.

Learn more:

Compound brainly.com/question/10585691

Noble gases brainly.com/question/1781595

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3 years ago
What does digital media allow you to do?
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3 years ago
Which TWO statements about the substances in the experiment are true?
nataly862011 [7]

Answer:

A and B are correct both are correct

4 0
2 years ago
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With which of the following statements would Whorf and Sapir agree?
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If the current through a 20-Ω resistor is 8.0 A , how much energy is dissipated by the resistor in 1.0 h ? Express your answer w
marshall27 [118]

Answer:

P(3600)=593.247W

Explanation:

First, let's find the voltage through the resistor using ohm's law:

V=IR=20*8=160V

AC power as function of time can be calculated as:

P(t)= V*I*cos(\phi)-V*I*cos(2 \omega t-\phi)  (1)

Where:

\phi=Phase\hspace{3}angle\\\omega= Angular\hspace{3}frequency

Because of the problem doesn't give us additional information, let's assume:

\phi=0\\\omega=2 \pi f=2*\pi *(60)=120\pi

Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):

P(3600)=160*8*cos(0)-160*8*cos(2*120\pi*3600-0)\\P(3600)=1280-1280*cos(2714336.053)\\P(3600)=1280-1280*0.5365255751\\P(3600)=1280-686.7527361=593.2472639\approx=593.247W

5 0
3 years ago
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