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jek_recluse [69]
3 years ago
13

GAMMA RAYS What are some applications of gamma rays? In other words, what can we use them for?

Physics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

Explanation:

Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells. Also, industry (sterilization and disinfection) and the nuclear industry.

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A camera of weight 8.9 newtons is dropped from a drone at a height of 18.6 meters and enters free fall. Assuming no air resistan
Svetlanka [38]

Answer:

19.09 m/s

Explanation:

u = 0, h = 18.6 m

Use third equation of motion

v^2 = u^2 + 2 g h

v^2 = 0 + 2 x 9.8 x 18.6

v = 19.09 m/s

4 0
4 years ago
A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
A pilot drops a bomb from a plane flying horizontally. Where will the plane be located when the bomb hits the ground
kumpel [21]

Answer:

The plane will be located directly above the bomb because they both have the same horizontal speed.

3 0
3 years ago
9. In the sun devil football game, a receiver, who is standing still, has caught a pass from the quarterback. Before he can move
otez555 [7]

Answer:

The mass of the receiver is 68.862 kg

Explanation:

Given;

let mass of the receiver be "m₁"

initial velocity of the receiver, u₁ = 0

mass of the tackler, m₂ =  156 kg

initial velocity of the tackler, u₂ = 6.89 m/s

their final velocity, v = 4.78 m/s

Apply the principle of conservation of linear momentum, for inelastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(m₁ x 0) + (156 x 6.89) = 4.78(m₁ + 156)

0 + 1074.84 = 4.78 (m₁ + 156)

1074.84 = 4.78 (m₁ + 156)

m₁ + 156 = 1074.84 / 4.78

m₁ + 156 = 224.862

m₁ = 224.862 - 156

m₁ = 68.862 kg

Therefore, the mass of the receiver is 68.862 kg

5 0
3 years ago
A​ hot-air balloon is 150 ft above the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) passes dir
Katyanochek1 [597]

Answer:

 dR/dt = 10.2 ft / s

Explanation:

Let's work this problem by finding the distance between the balloon and the motorcycle and then drift for the speed change of the distance

Balloon

      y = y₀ +v_{oy} t

Motorcycle

      x = v₀ₓ t

Distance, let's use Pythagoras' theorem

      R² = x² + y²

      R² = (v₀ₓ t)² + (y₀ + v_{oy} t)²

     v₀ₓ = 88 ft / s

     v_{oy} = 8 ft / s

     y₀ = 150 ft

     R² = (8 t)² + (150 + 8 t )²

     R² = 64 t² + (150 + 8t )²

This is the expression for the distance between the two bodies, the rate of change is the derivative with respect to time (d / dt)

         2RdR / dt = 64 2 t + 2 (150 + 8t) 8

        dR / dt = [64 t + (1200 + 64t )] / R

dR/dt = (1200 +128 t)/R

Let's calculate for the time of 10 s

        dR / dt = (1200 + 128 10) / R = 2480 /R

       R = √ [64 10² + (150 + 8 10)²

       R = √ [6400 + 52900]

       R = 243.5 ft

       dR / dt = (2480) / 243.5

       dR / dt = 10.2 ft / s

8 0
4 years ago
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