Answer:
0.7593 seconds
Explanation:
A student waiting at a stoplight notices that her turn signal, which has a period of 0.80 s, makes one blink exactly in sync with the turn signal of the car in front of her. The blinker of the car ahead then starts to get ahead, but 14 s later the two are exactly in sync again. What is the period of the blinker of the other car?
Speed:
If a car is moving on a track and car covers x meter distance in y second time. Now the car driver want to know the distance covered by the car in unit time. So the distance covered in unit time will be calculated by dividing x meters by y seconds. This quantity is known as the speed.
Given:
The period of the blinker of the student car is t1 = 0.80
The period after which both blinks sync is t2 = 15seconds
Let the period of the blinker of the other car be t2
The blinker of the student car is 1 second and can be calculated as:
Student car blink/ sec = 1/0.80
The blink of the other car is in 1 second and can be calculated as:
Other car blink/sec = 1/t2
According to the condition,
Other car blink/sec - students car blink /sec = 1/15
1/t2 - 1/0.80 = 1/15
1/t2 = 1/15 - 1/0.80
t2 = 0.7593
t2 = 0.7593second
Answer:
I found the experience tasking
Explanation:
I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.
I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn
Answer:
e e e e e e e e e e i have to write and i dont know what i could write
Answer:
the graph would lower down if we are talking about speed because the velocity stops going and theres no more kinetic energy to cause any speed
Explanation:
Answer:
Distance 5 km, Displacement 3 km east
Explanation: