Answer:
American Holly, Black Pine, Blue Pacific Juniper, Blue Dune Grass, Artemesia) MODERATELY SALT TOLERANT: plants always need protection from salt spray but will tolerate some inundations by storm surges. They are best used behind fences or buildings. (
False: No,any particles of matter do not have any potential or kinetic energy.
Answer:
Recycling and reuse of materials
Explanation:
One of the greatest problems facing the human population is the problem of solid waste disposal. The menace of solid waste disposal has led to the idea of landfills. Land fills are depressions on the earth surface prepared for the purpose of solid waste disposal.
The most important approach towards solid waste disposal is the idea of recycling of materials. A material can be collected after use and processed into the same material or serve as a precursor in another manufacturing process. This means that no waste is generated as the materials which are supposed to be disposed of as solid waste are processed into other useful materials. This will reduce the volume of solid wastes generated that may need to be disposed in a landfill.
The parent isotope is cobalt-59 (see the picture below).
The mass number is 59 and atomic number is 27 of the parent isotope.
Neutron activation is the process in which atomic nucleus capture free neutron or neutrons.
Cobalt-60 is produced in nuclear reactors in process of neutron activation from parent isotope cobalt-59 (see the picture below).
Atomic number (Z) is total number of protons and mass number (A) is total number of protons and neutrons in a nucleus.
Cobalt-59 and cobalt-60 are the isotopes of chemical element cobalt.
Isotopes are chemical elements with same atomic number (Z), but different mass number (different number of neutrons).
More about isotopes: brainly.com/question/364529
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Answer:
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>
A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.
Explanation:
1 mole HClO = 74.44g
0.0941g =
= 0.00126 moles
Concentration = no. of moles/volume in L
Hence, Concentration of HClO = 0.00126/ 0.250L
= 0.005M.
C1V1 =C2V2
0.005 × 250 mL = 0.2 × V2
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>