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S_A_V [24]
3 years ago
10

What is the hydrogen ion concentration in a 0.10M solution of KOH?​

Chemistry
1 answer:
dybincka [34]3 years ago
7 0

KOH is a strong base, so [OH-] = 0.10 M = 1.0 x 10^-1 M

[H+][OH-] = Kw

Kw = 1.0 x 10^-14

[H+] = 1.0 x 10^-14 / 1.0 x 10^-1 = 1.0 x 10^-13 M

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mamaluj [8]

Answer:

228.7dm^{3}

Explanation:

According to Boyle's law

P1V1 = P2V2

where P1& P2 are initial and final pressure

and V1& V2 and initial and final volumes respectively.

Given:

P1 = 136atm, P2 = 131.6atm

V1 = 142dm^{3}; V2 = ?

V2 = \frac{P1V1}{P2} = \frac{136*142}{131.6}

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Total volume, V = V1 + V2

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8 0
3 years ago
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8 0
3 years ago
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ankoles [38]

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Explanation:

6 0
3 years ago
BIOCR
Amiraneli [1.4K]

Answer:

Six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six

Explanation:

Hello there!

In this case, according to the molecular formula of the two moles of calcium phosphate:

2Ca_3(PO_4)_2

Thus, in order to calculate the atoms of each atom, it is necessary to multiply the two in front of the formula by the subscripts in the reaction:

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Best regards!

6 0
3 years ago
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Answer:

3.018 x 10⁻⁶ M.

Explanation:

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<em></em>

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<em />

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∴ s³ = 1.10 x 10⁻¹⁶/4 = 2.75 x 10⁻¹⁷.

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5 0
3 years ago
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