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natita [175]
2 years ago
10

Perform the operation of 147.02 / 0.338, and report the result with the proper number of significant figures

Physics
1 answer:
Ede4ka [16]2 years ago
4 0

Answer:

434.97041

Explanation:

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In nuclear physics wht units are used to measure the radius of an atom ?
Alecsey [184]
Angstrom = 10^-10 m
for nucleus size are used fermi (femtometer  10^-15 m )
6 0
3 years ago
An Ethernet cable is 4.00m long. The cable has a mass of 0.200kg . A transverse pulse is produced by plucking one end of the tau
Mashcka [7]

Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.

<h3>How much tension is in the cable?</h3>

The tension in the cable can be found as:

= 4 x mass x length x frequency

Solving for the frequency is:

= 1 / (0.800 / 4)

= 1 / 0.20

= 5.0 Hz

The tension is therefore:

= 4 x 0.20 x 4.00 x 5

= 80N

Find out more on tension at brainly.com/question/14336853

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4 0
1 year ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
vredina [299]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

7 0
3 years ago
Which fact about the moon, as seen from the earth, is evidence that the amount of time the Moon takes to complete one rotation a
Cerrena [4.2K]
Choice ' c ' is the evidence.
6 0
3 years ago
Read 2 more answers
You have a graduated cylinder that you use to measure volume. The cylinder
ad-work [718]

Answer:

D. 21 ml

Explanation:

Since, the cylinder is marked and graduated in the intervals if 1 ml. Therefore, the values between two consecutive ml, such as between 30 ml and 31 ml can not be determined. Because, we do not have any scale in between the ml. So, the least count of this instrument is 1 ml. This graduated cylinder can give the answers to zero decimal places, accurately. And it can not determine any decimal value due to its graduating or the marking limitation. So, all the options given, contain a decimal value, except for the option D. In option D there is no decimal value, hence it is a correct answer.

D. <u>21 ml</u>

5 0
3 years ago
Read 2 more answers
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