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3 years ago

10

The moon is not seen at all on the new moon.why???

1 answer:

tino4ka555 [31]3 years ago

5 0

<u>The moon is not seen at all on the new moon because:</u>

The moon itself doesn't make a light, it reflects sunlight. At the point when the moon lies between the Earth and the Sun, it is just the posterior of the moon that is light by the Sun. In this circumstance, the side of the moon confronting the Earth can't mirror any light whatsoever and seems dull.

The distinction between another moon and a sunlight based over-shadowing is during a sun oriented obscuration, the moon is actually in the position to completely obstruct the sun during the day.

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Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance

laila [671]

The time taken by traveler to cover the distance is,

$t=\frac{d}{v}$

Substitute the known values,

$\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}$

Therefore, the time taken by traveler to cover the distance is 89.3 s.

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1 year ago

In the Bohr model of the hydrogen atom, an electron (massm=9.1×10−31kg) orbits a proton at a distance of 5.3×10−11m. The proton

Marysya12 [62]

Answer:

$\omega = 6.557 \times 10^{16}\ rev/s$

Explanation:

GIVEN,

mass of electron = 9.1 x 10 kg

Radius = 5.3 x 10 m

pulling force = 8.2 x 10 N

Required centripetal for (Fe) for circular motion will be provided with electrical force (F)

$F = m_e\omega^2 r$

$\omega = \sqrt{\dfrac{F}{m_e\ r}}$

$\omega = \sqrt{\dfrac{8.2 \times 10^{-8}}{9.1 \times 10^{-31}\times 5.3 \times 10^{-11}}}$

$\omega = \sqrt{0.17 \times 10^{34}}$

ω = 4.12 x 10¹⁶ rad/s

$\omega = \dfrac{4.12 \times 10^{16}}{2\pi}$

$\omega = 6.557 \times 10^{16}\ rev/s$

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3 years ago

N which device is chemical energy transformed into electrical energy?

densk [106]

The answer is batteries

7 0

3 years ago

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The reaction between magnesium (Mg) and oxygen (O2) forms magnesium oxide (MgO).

Scorpion4ik [409]

Answer:

2 Mg + O2 = 2MgO

Type: Synthesis

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3 years ago

What is the acceleration due to gravity in a region where a simple pendulum having a length 75.000 cm has a period of 1.7357 s?

Ksju [112]

Answer:

Explanation:

T = 2π $\sqrt{L/g}$

(T / 2π)² = L/g

g = 4π²L/T²

g = 4π²(0.75000)/(1.7357)²

g = 9.82814766...

g = 9.8281 m/s²

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2 years ago