Question 5- is 9
question 6- is 9
question 7-is 4
question 8-is 21
Question 9-is 2
question 10-not sure sorry :(
Tell me if your right ;)
Answer:
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola
y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width =
Height =
Width =√10 and Height 
Step-by-step explanation:
Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)
are (h,k) and (-h,k).
Hence, the area of the rectangle will be (h + h) × k
Therefore, A = h²k ..... (2).
Now, from equation (1) we can write k = 5 - h² ....... (3)
So, from equation (2), we can write
![A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}](https://tex.z-dn.net/?f=A%20%3Dh%5E%7B2%7D%20%5B5-h%5E%7B2%7D%20%5D%3D5h%5E%7B2%7D%20-h%5E%7B4%7D)
For, A to be greatest ,

⇒ ![h[10-4h^{2} ]=0](https://tex.z-dn.net/?f=h%5B10-4h%5E%7B2%7D%20%5D%3D0)
⇒ 
⇒ 
Therefore, from equation (3), k = 5 - h²
⇒ 
Hence,
Width = 2h =√10 and
Height = 
Answer:
5
Step-by-step explanation:
We want the average arrests to be 4. It can be done by calculating the average between the average arrests and arrests during the 5th week, so we get:
Avg(1,2,3,4,5) = (Avg(1,2,3,4) + A(5)) / 2
Where Avg(x) is the average of arrests in given weeks, and A(x) is the number of arrests in a given week.
Solving for A(5) => A(5) = 2*Avg(1,2,3,4,5) - Avg(1,2,3,4) = 2 * 4 - 3 = 8-3 = 5
58 is the angle to the answer
If you have 5 pieces of something you split it up into 2 for each and then slip the last one into two.