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2 years ago

The sum of two numbers is 54 one exceed the other by 14 find the number

Chemistry

1 answer:

Aneli [31]2 years ago

7 0

Answer:

x=34

y=20

Explanation:

let the first number be 'x'

let the second number be 'y'

Equation 1:-

x + y = 54

Equation 2:-

x = y + 14 (Since one exceeds the other by 14)

Substituting Equation 2 in Equation 1:-

(y + 14) + y = 54

=> y + 14 + y = 54

=> 2y + 14 = 54

=> 2y = 54 - 14

=> 2y = 40

=> y = 40/2

=> y = 20

Now in Equation 1:-

x + y = 54

Substituting y=20,

x + 20 = 54

x = 54 - 20

x = 34

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The question is incomplete, the complete question is:

The solubility of slaked lime, $Ca(OH)_2$ , in water is 0.185 g/100 ml. You will need to calculate the volume of $2.50\times 10^{-3}$ M HCl needed to neutralize 14.5 mL of a saturated

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Explanation:

Given values:

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Volume of $Ca(OH)_2$ = 14.5 mL

Using unitary method:

In 100 mL, the mass of $Ca(OH)_2$ present is 0.185 g

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The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of $Ca(OH)_2$ = 0.0268 g

Molar mass of $Ca(OH)_2$ = 74 g/mol

Plugging values in equation 1:

$\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol$

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The chemical equation for the neutralization of calcium hydroxide and HCl follows:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O$

By the stoichiometry of the reaction:

Moles of $OH^-$ = Moles of $H^+$ = 0.000724 mol

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

Moles of HCl = 0.000724 mol

Molarity of HCl = $2.50\times 10^{-3}$

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3 years ago

The sum of two numbers is 54 one exceed the other by 14 find the number​

The sum of two numbers is 54 one exceed the other by 14 find the number