The answer is C radio waves are very high energy mechanical waves.
Answer:
1.3 × 10⁸ e⁻
Explanation:
When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:
20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻
1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:
2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻
Answer:
15.8 m/s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = [final velocity (v) – initial velocity (u)] / time (t)
a = (v – u) /t
With the above formula, we can obtain the final velocity of go-cart driver as follow:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
a = (v – u) /t
– 1.5 = (v – 32) / 10.8
Cross multiply
(v – 32) = –1.5 × 10.8
v – 32 = – 16.2
Collect like terms
v = – 16.2 + 32
v = 15.8 m/s
Therefore, the final velocity of go-cart driver is 15.8 m/s.
Answer:
See below
Explanation:
At point A the PE = mgh = 2 * 10 * 1 = 20 J
at point B, all of the PE , 20 J , is converted to Kinetic Energy
KE = 1/2 m v^2
20 = 1/2 (2)(v^2 )
20 = v^2 v = sqrt 20 = 4.47 m/s
for the friction part
vf = vo t + 1/2 a t^2 vf = final velocity = 0 (stopped)
vo = original velocity = 4.47 m/s
a = -1 m/s^2
0 = 4.47 t + 1/2 (-1) t^2
- .5t^2 + 4.47 t = 0
t ( -.5t+ 4.47) = 0 shows t = 4.47/.5 = 8.9 seconds
Answer:
Mass of the gold bar is 90.71 gram.
Explanation:
Given:
volume = 4.7 
density = 19.3 
To find:
mass = ?
Formula used:
density = 
Solution:
density is given by,
density =
mass = volume × density
mass = 4.7 × 19.3
mass = 90.71 g
Mass of the gold bar is 90.71 gram.
