Predict what will be observed in each experiment below. experiment predicted observation.

Chemistry

1 answer:

irga5000 [103]2 years ago

8 0

Answer:

The correct answer is -

1. a) The bubbles will shrink, some may vanish.

2. a) Can A will make a louder and stronger fizz than can B.

Explanation:

In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.

Thus, the correct answer would be - The bubbles will shrink, some may vanish

In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.

thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.

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For the reaction 2H2O > 2H2 + O2 what is the total number of moles of O2 produced from the complete decomposition of 8 moles

LekaFEV [45]

Answer: Option C) 4 moles

Explanation:

The reaction below shows the decomposition of 2 moles of water to yeild 2 moles of hydrogen and 1 mole of oxygen respectively.

2H2O(l) --> 2H2(g) + O2 (g)

So, if 2 moles of H2O produce 1 mole of O2

8 moles of H2O will produce Z mole of O2

To get the value of Z, cross multiply

2 x Z = 1 x 8

2Z = 8

Z = 8/2

Z = 4

Thus, 4 moles of O2 is produced from the complete decomposition of 8 moles H2O .

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Which substance will form a solution when mixed with solid sodium chloride?

s2008m [1.1K]

The substance that will form a solution when mixed with solid sodium chloride would be CH₂OH

<h3>Solubility of NaCl</h3>

A solution is only formed when a solute dissolves in a solvent.

In this case, $CCl4_$ and CH₂OH are the only liquid solvents. However, NaCl is insoluble in $CCl_4$ while it is soluble in CH₂OH due to its polarity.