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valentinak56 [21]
2 years ago
14

3. a) If the distance between two objects increases by a factor of 5 (5),

Physics
1 answer:
irina [24]2 years ago
3 0

Answer:

Answer for A

Explanation:

F1=GmM/r1^2

If r2 becomes r2=5r

F2=GmM/(25r^2)

Multiply with 25 gives to maintain the same force

I.e.,25F2=F1

F2=G(25m)M/25r^2=F1

By the factor 25 would change to increase to same.

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A certain spring is found not to obey Hooke’s law; it exerts a restoring force Fx(x)=−αx−βx2 if it is stretched or compressed, w
Masteriza [31]

Answer:U(x) = 30x^2 +6x^3

V^2=8.28m/s

Explanation:The law of conservation of energy is given by K1+U1= K2+U2 ...eq 1

Kinetic energy K.E= 1/2 mv^2

Restoring force function F(x)= -60x - 18x^2

But F(x)= -dU/dx

dU(x)=-F(x)dx

Integrating U(x)= -integral F(x)dx + U(0)

Substituting, we get

U(x) = - integral(-60x-18x^2)dx+U(0)

U(x)= 30x^2+6x^3+U(0)

U=0 at x=0

Therefore U(x)= 30x^2+6x^3

b) Given : x1=1.00m,x2= 0.50m ,V1=0, V2=?

Substituting into eq (a)

U1= 30(1.00)^2+6(1.00)^3=36J

Using x2=0.5 into eq(a)

U2=30(0.50)^2+6(0.50)^3=8.25J

Object at rest K1=0

0+36=K2+8.25

K2=27.75J

Given; m =0.900kg, V2=?

27.75=1/2×0.900×V2^2

V2= SQRT(2×27.75)/0.81

V2= 8.28m/s

4 0
4 years ago
Calculate the object's velocity as shown on the position-time graph,
Cloud [144]

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

4 0
3 years ago
Chemistry<br> determine the pressure
sashaice [31]
I think it's 1.03412969 or 1.03
8 0
4 years ago
150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc
Free_Kalibri [48]
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

3 0
4 years ago
The volume occupied by three milliliters of water is the same as three cubic centimeters of water
statuscvo [17]

The volume occupied by three milliliters of water is the same as three cubic centimeters of water is true. The conversion is as follows.

3mL (1 L/1000 mL) (1 m3/1000 L) (100 cm/1 m)^3 = 3 cm3

4 0
3 years ago
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