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2 years ago

3. a) If the distance between two objects increases by a factor of 5 (5),

Physics

1 answer:

irina [24]2 years ago

3 0

Answer:

Answer for A

Explanation:

F1=GmM/r1^2

If r2 becomes r2=5r

F2=GmM/(25r^2)

Multiply with 25 gives to maintain the same force

I.e.,25F2=F1

F2=G(25m)M/25r^2=F1

By the factor 25 would change to increase to same.

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$R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega$

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2) 4 W and 8 W

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$P=I^2 R$

where I is the current and R is the resistance.

For the first bulb:

$P_1 = (0.1 A)^2 (400 \Omega)=4 W$

For the second bulb:

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